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lara [203]
3 years ago
12

Which fraction is nearest in value

Mathematics
2 answers:
olganol [36]3 years ago
7 0

Answer:

it will be B took the test

Step-by-step explanation:

Lubov Fominskaja [6]3 years ago
4 0

Answer:

7/22

Step-by-step explanation:

You might be interested in
Is -2/3 and -0.8 greater than, less than, or equal to?
aniked [119]

Answer:

-2/3 is greater than -0.8

Step-by-step explanation:

-2/3 is greater than -0.8. If -2/3 forms to become a decimal it becomes 0.66 (repeated). It is closer to zero therefore causing it to be greater than -0.8.

5 0
3 years ago
A survey of 100 similar-sized hospitals revealed a mean daily census in the pediatrics service of 27 with a standard deviation o
Vinil7 [7]

Answer:

We conclude that the mean is greater than 25.  

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 25

Sample mean, \bar{x} = 27

Sample size, n = 100

Alpha, α = 0.05

Sample standard deviation, s = 6.5

First, we design the null and the alternate hypothesis

H_{0}: \mu = 25\\H_A: \mu> 25

We use One-tailed(right) z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{27 - 25}{\frac{6.5}{\sqrt{100}} } = 3.07

Now, z_{critical} \text{ at 0.05 level of significance } = 1.645

Since,  

z_{stat} > z_{critical}

We reject the null hypothesis and accept the alternate hypothesis.

Thus,  the mean is greater than 25.

3 0
3 years ago
A number is equal to twice a smaller number plus 3. The same number is equal to twice the sum of the smaller number and 1. How m
erma4kov [3.2K]
There are no solutions for this situation. =)
3 0
2 years ago
Read 2 more answers
A spherical water balloon has a diameter of 10 cm. How much water is needed to fill the balloon, in cubic centimeters? Round you
Helga [31]
You need to find the volume so, 4* \pi *r ^{3} / 3 = volume. So then we need the radius which would be 5. So, 5* \pi * 5 ^{3} / 3 = about 523.3 cm cubed
4 0
3 years ago
◆ Quadratic Equations ◆<br>Please help !
Mila [183]
I'm sure there's an easier way of solving it than the way I did, but I'm not sure what it could be. Never dealt with a problem like this before.

Anyway, I just plugged in and tested. Chose random values for a, b, c, and d, which follow the rule 0 < a < b < c < d:

a = 1
b = 2
c = 3
d = 4

\sf ax^2+(1-a(b+c))x+abc-d)

\sf 1x^2+(1-1(2+3))x+(1)(2)(3)-(4))

Simplify into standard form:

\sf x^2+(1-1(5))x+6-4

\sf x^2+(1-5)x+2

\sf x^2-4x+2

Use the quadratic formula to solve:

\sf x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

For functions in the form of \sf ax^2+bx+c. So in this case:

a = 1
b = -4
c = 2

Plug them in:

\sf x=\dfrac{4\pm\sqrt{(-4)^2-4(1)(2)}}{2(1)}

Solve for 'x':

\sf x=\dfrac{4\pm\sqrt{16-8}}{2}

\sf x=\dfrac{4\pm\sqrt{8}}{2}

\sf x\approx\dfrac{4\pm 2.83}{2}

\sf x\approx 0.59,3.41

So the answer would be A.
3 0
3 years ago
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