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-Dominant- [34]

4 years ago

9

Determine the range of the function graphed above.

1 answer:

Sever21 [200]4 years ago

8 0

Answer:

D. (-∞,4]

Step-by-step explanation:

The range is the y values

The lowest y values is negative infinity

The highest y values is 4

( - inf, 4]

We use the parentheses since we cannot get to negative infinity, the bracket since we reach 4

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Does anyone know the answer to this scale and unit conversion GED math problem? Thank you very much!

aliya0001 [1]

Answer:

Flour $5\dfrac{1}{2}\ c$

Sugar $2\dfrac{2}{3}\ c$

Butter $1\dfrac{1}{2}\ c$

Eggs $2$

Baking powder $7\ t$

Vanilla extract $3\ t$

Step-by-step explanation:

There will be 16 people at the party. Each person will eat 3 cookies, so all people will eat $16\cdot 3=48$ cookies.

Given cookie recipe makes 24 cookies, so to make 48 cookies you need

$48:24=2$ portions.

Thus,

1 portion 2 portions

Flour $2 \dfrac{3}{4}\ c$ $2\dfrac{3}{4}\cdot 2=2\cdot 2+\dfrac{3}{4}\cdot 2=4+\dfrac{3}{2}=4+1 \dfrac{1}{2}=5\dfrac{1}{2}\ c$

Sugar $1\dfrac{1}{3}\ c$ $1\dfrac{1}{3}\cdot 2=1\cdot 2+\dfrac{1}{3}\cdot 2=2+\dfrac{2}{3}=2\dfrac{2}{3}\ c$

Butter $\dfrac{3}{4}\ c$ $\dfrac{3}{4}\cdot 2=\dfrac{3}{2}=1\dfrac{1}{2}\ c$

Eggs $1$ $1\cdot 2=2$

Powder $3\dfrac{1}{2}\ t$ $3\dfrac{1}{2}\cdot 2=3\cdot 2+\dfrac{1}{2}\cdot 2=6+1=7\ t$

Vanilla $1\dfrac{1}{2}\ t$ $1\dfrac{1}{2}\cdot 2=1\cdot 2+\dfrac{1}{2}\cdot 2=2+1=3\ t$

8 0

3 years ago

Rachel drew the two graphs below. Graph R On a coordinate plane, a line goes through points (0, 0) and (2, 1). Graph S On a coor

fgiga [73]

Answer:d

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

3 times the sum of a number and 4

Lyrx [107]

Answer:

3(4+x)

which can be simplified to 12+3x

4 0

4 years ago

Classify each function as even, odd, or neither even nor odd.

drek231 [11]

The function

f(x) is even

g(x) is neither even nor odd

h(x) is odd

Steps:

for an even function it holds that f(-x) = f(x):

f(-x) = (-1)^6 x^6 - (-1)^4 x^ 4 = x^6 - x^4 = f(x) => f is even

for an odd h(x) it holds that h(-x) = -h(x):

$h(-x) = (-1)^5x^5-(-1)^3x^3 = -(x^5-x^3) = -h(x) \implies h(x)\,\, \mbox{even}$

It is easy to show that g(x) does not match any of the two possibilities above.

8 0

3 years ago

Read 2 more answers

Pls help me with this question.

maw [93]

Answer:

The slope for this equation is $\frac{1}{7}$ .

Step-by-step explanation:

x y

point 1: -4 -3

point 2: 3 -2

slope: $\frac{1}{7}$

To solve for slope here is an equation, to help: $\frac{y^2-y^1}{x^2-x^1}$

$\frac{y^2-y^1}{x^2-x^1} \\\\\frac{-2-(-3)}{3-(-4)} \\\\= \frac{1}{7} \\$

5 0

3 years ago