If x2 mx m is a perfect-square trinomial, which equation must be true?.
1 answer:
Expression consist of numbers, variables, and mathematical operations. The equation that is true is x²+mx+m= (x+2)².
<h3>What is an Expression?</h3>In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.
As it is given that the x²+mx+m is a perfect square trinomial, and we know that the general equation of perfect square trinomial is given as,
ax²+bx+c=0
where a,b and c are real numbers, and a≠0,
if we compare the equation with our equation
We will get the value of 'a' as 1, b=c=m, therefore, we need a binomial which is when expanded then in its perfect square trinomial the value of b=c, therefore, the only feasible option here is (x+2)².
Hence, the equation that is true is x²+mx+m= (x+2)².
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Answer:
1). 0.903547
2). 0.275617
Step-by-step explanation:
It is given :
K people in a party with the following :
i). k = 5 with the probability of
ii). k = 10 with the probability of
iii). k = 10 with the probability
So the probability of at least two person out of the 'n' born people in same month is = 1 - P (none of the n born in the same month)
= 1 - P (choosing the n different months out of 365 days) =
1). Hence P(at least 2 born in the same month)=P(k=5 and at least 2 born in the same month)+P(k=10 and at least 2 born in the same month)+P(k=15 and at least 2 born in the same month)
=
=
= 0.903547
2).P( k = 10|at least 2 share their birthday in same month)
=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)
=
= 0.0.275617