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tatuchka [14]
2 years ago
6

If x2 mx m is a perfect-square trinomial, which equation must be true?.

Mathematics
1 answer:
kodGreya [7K]2 years ago
7 0

Expression consist of numbers, variables, and mathematical operations. The equation that is true is x²+mx+m= (x+2)².

<h3>What is an Expression?</h3>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

As it is given that the x²+mx+m is a perfect square trinomial, and we know that the general equation of perfect square trinomial  is given as,

ax²+bx+c=0

where a,b and c are real numbers, and a≠0,

if we compare the equation with our equation

ax^2+bx+c=0\\x^2+mx+m=0

We will get the value of 'a' as 1, b=c=m, therefore, we need a binomial which is when expanded then in its perfect square trinomial the value of b=c, therefore, the only feasible option here is (x+2)².

Hence, the equation that is true is x²+mx+m= (x+2)².

Learn more about Expression:

brainly.com/question/13947055

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HELP PLEASE FAST!! ILL GIVE 5 STARS :))))
VMariaS [17]
Use substitution when either and x or y is given, for instance: x = 2y + 3 or y = 8x - 9.

Use elimination when a number from both equations can cancel each other out, for example:
2x + 3y = 19
-2x + 7y = 12

Hope this helps!
4 0
3 years ago
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Write a formula for the maximum number of segments determined by n points
jeyben [28]
Let n = the number of points
(x-1) + ... (x-x)

The last term will always be 0, when you reach that, stop.

ex. 1pt: 1-1=0
      2pt: (2-1) + (2-2) = 1
      3pt: (3-1) + (3-2) + (3-3) = 3

7 0
3 years ago
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valentina_108 [34]
C.) It increases ............
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What is (-4,9) as an inequality
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4 0
2 years ago
Part 2. State what additional information is required in order to know that the triangles are congruent by ASA.​
Helga [31]
<h3>Answer: Choice D. \angle SQR \cong \angle XQR</h3>

The red angle markers show those two angles are congruent. That's one "A" of "ASA". The S refers to a congruent pair of sides. We don't have any tickmarks to indicate congruent pairs; however, we do know that QR = QR is a shared side that overlaps (reflexive theorem). So this is the "S" in "ASA".

The thing missing is the angle Q of the top triangle, and also of the bottom triangle as well. If we know those two angles are congruent, then we have enough info to use ASA. More specifically, if we know that \angle SQR \cong \angle XQR, then we can use ASA.

One thing to notice is that the other answer choices involve side lengths and not angles. This implies that if A, B or C were one of the answers, then we would have something like SAS or SSS. But instead we want ASA. So we can immediately rule choices A,B, and C out.

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