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3 years ago

I will give brainliest answer pls help

Mathematics

2 answers:

zaharov [31]3 years ago

8 0

Answer:

Step-by-step explanation:

1/4= 0.25

FromTheMoon [43]3 years ago

6 0

Answer:

Step-by-step explanation:

Constant of proportionality is basically a ratio, or a unit rate.

For example, if there was the ratio 1:3, the COP (constant of proportionality) would be 3. If one pencil costs 50c, then the COP is .50 or 1/2.

In this problem, y is the single unit, and the COP is 0.25. That means that we need to find a unit rate that is multiplying by 0.25, or 1/4. This is found in option C.

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Solve pls brainliest

Goshia [24]

Answer:

4.5341 < 6.9 < 6.906 < 6.96

Step-by-step explanation:

4.5341 is closer to 0 than 6.96 is.

8 0

2 years ago

Solve negative 8 over 5, the whole multiplied by x minus 6 equals negative 54. A 15

Verdich [7]

-8/5x - 6 = -54....multiply by 5 to get rid of fractions
-8x - 30 = - 270
-8x = -270 + 30
-8x = - 240
x = -240/-8
your answer is 30

4 0

3 years ago

Read 2 more answers

The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.

Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m + 40 m + c = 120 m

61 m + c = 120 m

c = 120 m - 61 m

c = 59 m

↓ ↓

A → → → → → → → → → → → C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

$a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0$

Angle B is calculated as follows;

$Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0$

Angle C is calculated as follows;

$Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0$