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Mamont248 [21]
2 years ago
15

28% of 63 is what? i'm so confused right now

Mathematics
2 answers:
Daniel [21]2 years ago
6 0

Answer:

\displaystyle 17\frac{16}{25}

Step-by-step explanation:

\displaystyle 28\%\:of\:63 \\ \\ \frac{7}{25} \times 63 = \frac{441}{25} \\ \\ \boxed{\boxed{17\frac{16}{25}}}

To turn 63% into a fraction, write it as a fraction over 100, then simplify it:

\displaystyle \boxed{\frac{7}{25}} = \frac{28}{100}

I am joyous to assist you at any time.

olasank [31]2 years ago
4 0

28% x 63

28 over 100 x 63 over 1

=

17.64

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Rewrite the system of linear equations as a matrix equation AX = B.
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Answer:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

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From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]

And the vector of vriables (X) is:

\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

In conclusion, AX=B is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

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