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Illusion [34]
2 years ago
13

Can't figure this out, have been trying for a half hour now.

Mathematics
1 answer:
Likurg_2 [28]2 years ago
7 0

Answer:

45

Step-by-step explanation:

this is correct this is correct

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1.consider the function
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Function transformation involves changing the form of a function

  • The transformation from f(x) to g(x) is a horizontal shift 3 units left, followed by a vertical stretch by a factor of 4
  • The x and y intercepts are -0.67 and 1.91, respectively.
  • The behavior of g(x) is that, g(x) approaches infinity, as x approaches infinity.

The functions are given as:

\mathbf{f(x) = log3x}

\mathbf{g(x) = 4log3(x+1)}

<u>(a) The transformation from f(x) to g(x)</u>

First, f(x) is shifted left by 1 unit.

The rule of this transformation is:

\mathbf{(x,y) \to (x + 1,y)}

So, we have:

\mathbf{f'(x) = log3(x + 1)}

Next. f'(x) is vertically stretched by a factor of 4.

The rule of this transformation is:

\mathbf{(x,y) \to (x,4y)}

So, we have:

\mathbf{g(x) = 4log3(x+1)}

Hence, the transformation from f(x) to g(x) is a horizontal shift 3 units left, followed by a vertical stretch by a factor of 4

<u>(b) Sketch of g(x)</u>

See attachment

<u>(c) Asymptotes</u>

The graphs of g(x) have no asymptote

<u>(d) The intercepts, and the behavior of f(x)</u>

The graph crosses the x-axis at x =-0.67, and it crosses the y-axis at y = 1.91

Hence, the x and y intercepts are -0.67 and 1.91, respectively.

The behavior of g(x) is that, g(x) approaches infinity, as x approaches infinity.

We know this because, the value of the function increases as x increases

Read more about function transformations at:

brainly.com/question/13810353

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Hope this helps! :)
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