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Zanzabum
2 years ago
14

What's 2/3 divided by 5

Mathematics
2 answers:
rusak2 [61]2 years ago
8 0
2/15 as a fraction and decimal form is 0.13-
gtnhenbr [62]2 years ago
4 0

Answer:2/15

Step-by-step explanation:

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A right angle is 90 degrees, an obtuse angle is larger than 90 degrees and an acute angle is less than 90 Degrees.

The angle shown is smaller than 90 degrees so it is c. Acute

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Taj asked 27 classmates whether they know how to write calligraphy .
sukhopar [10]

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so

Step-by-step explanation:

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3 years ago
Sally read 13 books during this month.her brother read 7 books.one fourth of all books they read were non fiction. how many non
vladimir1956 [14]
Thirteen plus seven is twenty. One fourth of twenty is five.
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3 0
3 years ago
Define z_alpha to be a z-score with an area of alpha to the right. For Example: z_0.10 means P(Z > z_0.10) = 0.10. We would a
Reptile [31]

Answer:

a) P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

"=NORM.INV(0.025,0,1)"

And for this case the two values are :z_{crit}= \pm 1.96

b) P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates \alpha/2 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

"=NORM.INV(alpha/2,0,1)"

c) For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got z_{\alpha/2}=1.64

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Part a

P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

"=NORM.INV(0.025,0,1)"

And for this case the two values are :z_{crit}= \pm 1.96

Part b

P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates \alpha/2 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

"=NORM.INV(alpha/2,0,1)"

Part c

For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got z_{\alpha/2}=1.64

6 0
3 years ago
What are two ratios equvilant to 8:6?
disa [49]
4:3 (simplified) and 16:12 (doubled) both work
Hope this helps!
8 0
3 years ago
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