8j-k + 14 when j = 0.25 and k = 1
2 answers:
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Tyler concludes that 5x² will always have a larger output for the same value of x.
<u>Look at the graph below and the table given</u>
Take a random value: x = 0
- When 5x², y = 0
- When 2^x, y = 1
Here, 1 > 0, making 2^x > 5x²
Hence, 2^x is greater than 5x² at this point. making Tyler's point not applicable.
Disagree with Tyler's point.
