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Leokris [45]
2 years ago
10

Find an expression which represents the sum of (6x-4)(6x−4) and (-2x+5)(−2x+5) in simplest terms

Mathematics
1 answer:
denpristay [2]2 years ago
7 0

Answer:

40x^2-68x+41

Step-by-step explanation:

Multiply both expressions

(-2x+5)^2=  4x^2-20x+25

(6x-4)^2=36x^2-48x+16

Then add

Use multiplication table if you have difficulty with multiplying

Ex

      -2x       5

-2x  4x^2  -10x

5     -10x    25

Then add them all to get the full expression

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Read 2 more answers
1) AU (C - B) =
torisob [31]

Answer:

A \cup (C-B) = (A \cup C) \cap  (A \cup B^c)\\A \cup (B \cap C) = (A \cup B) \cap (A \cup C) \,\,\, \text{Here you use double inclusion.}\\A \cup B \cup C =  A \cup (B \cup C)\\B^c \cap (A-C)  = (B^c - C) \cap A\\(B \cap C) - A = (B-A)\cap C\\C-(A\cup B) =  (C - A )\cap B\\A^c \cap (B \cap C) = ( A^c \cap B) \cap C

Step-by-step explanation:

A \cup (C-B) = A \cup (C \cap B^c) = (A \cup C) \cap  (A \cup B^c)\\A \cup (B \cap C) = (A \cup B) \cap (A \cup C) \,\,\, \text{Here you use double inclusion.}\\A \cup B \cup C = (A \cup B ) \cup C  = A \cup (B \cup C)\\B^c \cap (A-C)  = B^c \cap (A \cap C^c) =  (B^c \cap C^c) \cap A =  (B^c - C) \cap A\\(B \cap C) - A = (B \cap C) \cap A^c  = (B \cap C) \cap A^c = (B \cap A^c)\cap C = (B-A)\cap C\\C-(A\cup B) = C \cap (A\cup B)^c = C \cap (A^c \cap B^c ) = (C  \cap A^c )\cap B^c = (C - A )\cap B\\

A^c \cap (B \cap C) = ( A^c \cap B) \cap C

3 0
3 years ago
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