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Darina [25.2K]
3 years ago
12

The space shuttle carries c pounds of cargo, and each piece of cargo weighs 158.14 pounds. Which of the following expressions re

presents the number of pieces of cargoThe space shuttle carries c pounds of cargo, and each piece of cargo weighs 158.14 pounds. Which of the following expressions represents the number of pieces of cargo?
A. c × 158.14
B. c ÷ 158.14
C. c - 158.14
D. c + 158.14
Mathematics
2 answers:
Allushta [10]3 years ago
6 0

Answer:

The correct answer would be B

Step-by-step explanation:


lawyer [7]3 years ago
5 0

Answer:

The answer would be B. c ÷ 158.14

Hope this helps you!


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What is -2n-5k+8-4n-11=-7
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Answer:

n= 2/3 - 5/6k , ker

Step-by-step explanation:

-2n-5k+8-4n-11=-7

-6n-5k+8-11=-7

-6n=-7+3+5k

-6n=-4+5k

then divide both sides by -6 to get your answer

n= 2/3 - 5/6k , ker

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One glass of milk gives you 3/10 of the recommended amount of calcium per day.
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9/10 of the recommended amount.
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Luis wants to buy a skateboard that usually sells for $79.20. All merchandise is discounted by 12%. What is the total cost of th
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Answer:

$74.75

Step-by-step explanation:

When it comes to tax, the sales tax is applied <em>after</em> the discount is provided by the store, as long as it is something like a direct store coupon or a discounted price. In this case, it is a discounted price by the store, so we will include sales tax after.

$79.20 after a 12% discount becomes $69.70 (or $69.696).

The state tax applies to this new price.

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5 0
3 years ago
A farmer who grows genetically engineered corn is experiencing trouble with corn borers. A random check of 5,000 ears revealed t
Ivenika [448]

Answer:

Probability that an ear of corn selected at random will contain no borers is 0.4966.

Step-by-step explanation:

We are given that the distribution of the number of borers per ear approximated the Poisson distribution. The farmer counted 3,500 borers in the 5,000 ears.

Let X = <u><em>Number of borers per ear</em></u>

The probability distribution of the Poisson distribution is given by;

P(X=x) = \frac{e^{-\lambda }\times \lambda^{x}  }{x!}  ; x = 0,1,2,3,......

where, \lambda = parameter of this distribution and in our question it is proportion of bores in the total ears =  \frac{3500}{5000}  = 0.7

SO, X ~ Poisson(\lambda = 0.7)

Now, probability that an ear of corn selected at random will contain no borers is given by = P(X = 0)

                            P(X = 0)  =  \frac{e^{-0.7}\times 0.7^{0}  }{0!}

                                           =  e^{-0.7} = <u>0.4966</u>

Hence, the required probability is 0.4966.

6 0
3 years ago
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