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Margaret [11]
2 years ago
9

Find the equation of a line that passes through the points (3,2) and (5,6).

Mathematics
2 answers:
Debora [2.8K]2 years ago
7 0

Answer:

Step-by-step explanation:This particular answer works out to be undefined because it is a straight line and there is no slope and no equation for it. I will show you how to work it out though so you will know how to do it with other problems. We will still be using the y = mx + b formula. First step is to find m. In order to find the slope we would use the equation:

m = (y2 - y1) / (x2 - x1) Note: The number behind the letter designates which x or y value you will use of the 2 (x, y) plots

m = (-5 - 2) / (3 - 3)

m = -7 / 0 Note: A number divided by 0 is undefined which means your slope is undefined

Since your slope is undefined your equation would be x = 3 because your x values are both 3.

Now let's assume your second (x, y) plot was actually (-3, -5).

m = (-5 - 2) / (-3 - 3)

m = -7 / - 6 Note: A negative divided by a negative is a positive. The negatives cancel each other out.

m = 7/6

Okay now back to our slope-intercept formula.

y = 7/6x + b

Now in order to figure out what b is, we will again take the plot point and plug the values into the equation. You can use either point because either way the answer will come out the same. In this case we will use (3, 2).

2 = 7/6(3) + b

2 = 21/6 + b Note: The easiest way to do the next part is to make the 2 into a fraction over 6

12/6 - 21/6 = b

-9/6 = b or -3/2

So now all we have to do is plug this value into our equation.

y = 7/6x - 3/2

Feliz [49]2 years ago
3 0
Formula
y-y2=m(x-x2)

m=(y2-y1)/(x2-x1)

let
(x1,y1)=(3,2)
and
(x2,y2)=(5,6)


m=(6-2)/(5-3)
=2
y-y2=m(x-x2)
y-6=2(x-5)
y=2x-10+6
y=2x-4


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Solve the system by using the inverse of the coefficient matrix. -3x + 9y = 9 3x + 2y = 13 Group of answer choices
kirill [66]

Answer:

x= 3

y=2

Step-by-step explanation:

-3x + 9y = 9 ----------- equation 1

3x + 2y = 13--------------- equation 2

In  Matrix Form                            

\left[\begin{array}{cc}-3&9\\3&2\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}9\\13\end{array}\right]                  

Let A = \left[\begin{array}{cc}-3&9\\3&2\end{array}\right]    X =  \left[\begin{array}{c}x\\y\end{array}\right]  and B =    \left[\begin{array}{c}9\\13\end{array}\right]  

Then Mathematically AX= B

or X= A⁻¹ B

Where A⁻¹ = Adjacent A/ mod of A

Adjacent A =   \left[\begin{array}{cc}2&-9\\-3&-3\end{array}\right]    

Mod Of A= -6 - (27) = -33 which is not equal to zero

so Putting These values in the given formula

X= 1/-33    \left[\begin{array}{cc}2&-9\\-3&-3\end{array}\right]      \left[\begin{array}{c}9\\13\end{array}\right]  

Now Multiplying Rows and Columns

   \left[\begin{array}{c}x\\y\end{array}\right] = -1/33    \left[\begin{array}{cc}2*9+- 9*13\\-3*9 +- 3*13\end{array}\right]

Solving the Matrix we get

  \left[\begin{array}{c}x\\y\end{array}\right] = -1/33  \left[\begin{array}{cc}18-117\\-27-39\\\end{array}\right]

  \left[\begin{array}{c}x\\y\end{array}\right] = -1/33  \left[\begin{array}{cc}-99\\-66\end{array}\right]

From Here we find x= 99/33 or 3

and y = 66/33= 2

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elena-14-01-66 [18.8K]
(C) 1000,
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Henry is being paid $11.25 an hour at his job before he pays taxes. However, 28% is subtracted from his wages earned for taxes.
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Hi, Kaylasole99! :)

11.25*28%
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11.25-3.15
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With taxes deducted, Henry makes $8.10 an hour.

To find how many hours he needs to work to make $324, we can create an equation:
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Solve for x.
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Divide both sides by 8.10.
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x=40

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