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Kobotan [32]
3 years ago
15

The graphs of functions f(x) and g(x) = f(x) + k are shown below:

Mathematics
2 answers:
IrinaVladis [17]3 years ago
8 0
The answer is -2 . I hope it helps
.
ycow [4]3 years ago
7 0

Answer:

Answer: -2

Step-by-step explanation:

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99 Points!
patriot [66]
Simple...

you have: 

1.) Find the slope of the line using (-2,1) and (3,6)

Using \frac{ y_{1}-  y_{2} }{ x_{1} - x_{2}  }

\frac{1-6}{-2-3} = \frac{-5}{-5}

m=1 (slope)

2.)Tell whether the equation, 8y+3=5x+3, is a direct variation.

y=\frac{5x}{8} (None)

3.)What is the slope and y-intercept of the graph of the equation y=2x+3?

Slope =2 

y-intercept=3

C.

Thus, your answer.
3 0
2 years ago
At noon, ship A is 170 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 20 km/h. How fast is
garik1379 [7]
Check the picture below.

now, keep in mind that ship B is going at 20kph, thus from noon to 4pm, is 4 hours, so it has travelled by then 20 * 4 or 80 kilometers, thus b = 80.

whilst the ship B is moving north, the distance "a" is not really changing, and thus is a constant, that matters because the derivative of a constant is 0.

\bf c^2=a^2+b^2\implies \stackrel{chain~rule}{2c\cfrac{dc}{dt}}=0+2b\cfrac{db}{dt}\implies \cfrac{dc}{dt}=\cfrac{b\frac{db}{dt}}{c}
\\\\\\
\begin{cases}
\frac{db}{dt}=20\\
c=10\sqrt{353}\\
b=80
\end{cases}\implies \cfrac{dc}{dt}=\cfrac{80\cdot 20}{10\sqrt{353}}\implies \cfrac{dc}{dt}=\cfrac{160}{\sqrt{353}}
\\\\\\
\textit{and rationalizing the denominator}\implies \cfrac{160\sqrt{353}}{353}

8 0
3 years ago
The diameter of a circle is 20 ft. Find its area in terms of T.
Ksivusya [100]

Answer:

314.2ft^2

Step-by-step explanation:

Given data

Diameter= 20ft

Radius r= 20/2= 10ft

The expression for the area is

A= πr^2

A= 3.142*10^2

A= 3.142*100

A= 314.2ft^2

Hence the area is 314.2ft^2

5 0
3 years ago
.-- .... .- - .. ... ..--- .-.-. ..--- ..--..
Andrej [43]

Oh so easy!

The answer is 4!

The question is

WHAT IS 2+2?

It's written in morse code! I used to study it! :)

7 0
2 years ago
GIVING BRAINLIEST WHOEVER ANSWER THIS CORRECT THANK U.
Sonja [21]

Answer:

The coordinates of Y' and Z' are, respectively Y'(6,-1) Z'(-2,0)

Step-by-step explanation:

Translations

A given point A(x,y) when translated by the rule (h,k) maps to A'(x+h,y+k).

We are given the point X(3,-2) and its image at X'(2,-4). The rule for the translation used is:

(h,k)=(2,-4)-(3,-2)=(2-3,-4+2)=(-1,-2)

If we apply the same translation to the point Y(7,1) we get the image Y'(7-1,1-2)=Y'(6,-1).

If we apply the same translation to the point Z(-1,2) we get the image Z'(-1-1,2-2)=Z'(-2,0).

The coordinates of Y' and Z' are, respectively Y'(6,-1) Z'(-2,0)

it's a example from another eqaqthion

6 0
2 years ago
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