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sammy [17]
2 years ago
11

Answer quickkkkkkkkkkk

Mathematics
2 answers:
Hoochie [10]2 years ago
6 0

Answer:

last oneeee

Step-by-step explanation:

asambeis [7]2 years ago
6 0
Since it is in the bottom left corner both the x and y coordinates are gonna be negative so it is
Negative x coordinates and negative y coordinates
You might be interested in
Susan works as a tutor for $10 and hour, and as a waitress for $11 an hour. This month, she worked a combined total of 90 hours
uysha [10]

Answer:

\$(990-t)

Step-by-step explanation:

The correct question is

Susan works as a tutor for $10 and hour, and as a waitress for $11 an hour. This month, she worked a combined total of 90 hours at her two jobs. Let t be the number of hours Susan worked as a tutor this month. Write an expression for the combined total dollar amount she earned this month

Let

t -----> the number of hours that Susan work as a tutor

y ----> the number of hours that Susan work as a waitress

z ---> the combined total dollar amount she earned this month

we know that

t+y=90

y=90-t-----> equation A

we know that

The combined total dollar amount she earned this month is equal to the number of hours that Susan work as a tutor multiplied by $10 plus the number of hours that Susan work as a waitress multiplied by $11

z=10t+11y ----> equation B

substitute equation A in equation B

z=10t+11(90-t)

z=10t+990-11t

z=990-t

therefore

The expression for the combined total dollar amount is $(990-t)

3 0
3 years ago
Jeff wants to spend at most $89 on his mom's birthday gifts. He already bought her a
Andrew [12]

The Inequality representing money she can still spend on her friend birthday gift is .

Jordan can still spend at most $30 on her friends birthday gift.

Step-by-step explanation:

Given:

Total money need to spend at most = $45

Money spent on Yoga ball = $15

We need to find how much money she can still spend on her friend birthday gift.

Solution:

Let the money she can still spend on her friend birthday gift be 'x'.

So we can say that;

Money spent on Yoga ball plus money she can still spend on her friend birthday gift should be less than or equal to Total money need to spend.

framing in equation form we get;

The Inequality representing money she can still spend on her friend birthday gift is .

On solving the the above Inequality we get;

we will subtract both side by 15 using subtraction property of Inequality.

Hence Jordan can still spend at most $30 on her friends birthday gift.

4 0
2 years ago
Let $s$ be a subset of $\{1, 2, 3, \dots, 100\}$, containing $50$ elements. how many such sets have the property that every pair
Tamiku [17]

Let A be the set {1, 2, 3, 4, 5, ...., 99, 100}.

The set of Odd numbers O = {1, 3, 5, 7, ...97, 99}, among these the odd primes are :

P={3, 5, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}

we can count that n(O)=50 and n(P)=24.

 

 

Any prime number has a common factor >1 with only multiples of itself.

For example 41 has a common multiple >1 with 41*2=82, 41*3=123, which is out of the list and so on...

For example consider the prime 13, it has common multiples >1 with 26, 39, 52, 65, 78, 91, and 104... which is out of the list.

Similarly, for the smallest odd prime, 3, we see that we are soon out of the list:

3, 3*2=6, 3*3=9, ......3*33=99, 3*34=102.. 

we cannot include any non-multiple of 3 in a list containing 3. We cannot include for example 5, as the greatest common factor of 3 and 5 is 1.

This means that none of the odd numbers can be contained in the described subsets.

 

 

Now consider the remaining 26 odd numbers:

{1, 9, 15, 21, 25, 27, 33, 35, 39, 45, 49, 51, 55, 57, 63, 65, 69, 75, 77, 81, 85, 87, 91, 93, 95, 99}

which can be written in terms of their prime factors as:

{1, 3*3, 3*5, 3*7, 5*5,3*3*3, 3*11,5*7, 3*13, 2*2*3*3, 7*7, 3*17, 5*11 , 3*19,3*21, 5*13, 3*23,3*5*5, 7*11, 3*3*3*3, 5*17, 3*29, 7*13, 3*31, 5*19, 3*3*11}

 

1 certainly cannot be in the sets, as its common factor with any of the other numbers is 1.

3*3 has 3 as its least factor (except 1), so numbers with common factors greater than 1, must be multiples of 3. We already tried and found out that there cannot be produced enough such numbers within the set { 1, 2, 3, ...}

 

3*5: numbers with common factors >1, with 3*5 must be 

either multiples of 3: 3, 3*2, 3*3, ...3*33 (32 of them)

either multiples of 5: 5, 5*2, ...5*20 (19 of them)

or of both : 15, 15*2, 15*3, 15*4, 15*5, 15*6 (6 of them)

 

we may ask "why not add the multiples of 3 and of 5", we have 32+19=51, which seems to work.

The reason is that some of these 32 and 19 are common, so we do not have 51, and more important, some of these numbers do not have a common factor >1:

for example: 3*33 and 5*20

so the largest number we can get is to count the multiples of the smallest factor, which is 3 in our case.

 

By this reasoning, it is clear that we cannot construct a set of 50 elements from {1, 2, 3, ....}  containing any of the above odd numbers, such that the common factor of any 2 elements of this set is >1.

 

What is left, is the very first (and only) obvious set: {2, 4, 6, 8, ...., 48, 50}

 

<span>Answer: only 1: the set {2, 4, 6, …100}</span>

8 0
3 years ago
Need help please would really be greatful
Rainbow [258]

Answer:

122°  

Step-by-step explanation:

The formula for finding the sum of all angles in a polygon is:

(n-2) * 180°

n is the number of angles

Here n = 7, so the sum of all angles is

(7-2) * 180°  = 900°

x = 900 - 128 - 130 - 120 - 115 - 145 - 140 = 122°

Make me the brainliest ;)

7 0
2 years ago
Point A is at (-7,5) and point B is at (7,3) what is the midpoint
AleksandrR [38]

Answer:

The midpoint between A(-7, 5) and B (7, 3) is: (0, 4)

Step-by-step explanation:

Given the points

  • A (-7, 5)
  • B (7, 3)

Determining the midpoint between A(-7, 5) and B (7, 3)

M.P_{AB\:}=\:\:\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

\left(x_1,\:y_1\right)=\left(-7,\:5\right),\:\left(x_2,\:y_2\right)=\left(7,\:3\right)

             =\left(\frac{7-7}{2},\:\frac{3+5}{2}\right)

             =\left(0,\:4\right)

Therefore, the midpoint between A(-7, 5) and B (7, 3) is: (0, 4)

8 0
2 years ago
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