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weqwewe [10]
2 years ago
15

Different Betweens in SRAM and DRAM !

Computers and Technology
2 answers:
den301095 [7]2 years ago
5 0

Answer:

Explanation:

<u>Application Differences:</u>

<u>SRAM</u>

SRAM stands for Static Random Access Memory  DRAM stands for Dynamic Random Access Memory

Faster access is due to the usage of transistors to store single bit of data  

SRAMs are used for cache memories due to faster access time  

<u>DRAM</u>

DRAM stands for Dynamic Random Access Memory

DRAMs are used for main memories due to comparatively slower access time.

DRAMs use capacitor to store bits where each capacitor holds a single bit

<u>Parameter differences</u>  

<u>Speed:</u> SRAMs are faster due to presence of transistors. DRAMs are slower due to presence of capacitors

<u>Size:</u> Due to complexity involved in the internal circuits, SRAMs are smaller in capacity for same size of the chip. DRAMs are larger as compared to SRAMs since their capacity for a given physical size is more.

<u>Cost:</u> SRAMs are costlier and the per bit storage cost is more than that of the DRAMs. DRAMs are cheaper and the per bit storage cost is less than that of the SRAMs

Vinvika [58]2 years ago
4 0
<h3><u> </u><u>SRAM </u><u>:</u></h3>

  • SRAM has lower access time, so it is faster compared to DRAM.
  • SRAM is costlier then DRAM.
  • SRAM requires constant power supply, which means this type of memory consumes more power.
  • Due to complex internal circuitry, less storage capacity is available compare to the same physical size of DRAM memory chip.
  • SRAM has low packaging density.

<h3><u>DRAM </u><u>:</u></h3>

  • DRAM has higher access time, so it is lower than SRAM.
  • DRAM costs less compair to the SRAM.
  • DRAM offers reduced power consumption, due to the fact that the information is stored in capacitor.
  • Due to the small internal circuitry in the one-bit memory cell of DRAM, the large storage capacity is available.
  • DRAM has high packaging density.

<h3>Hope Helps!!</h3>

You might be interested in
Write a program that accepts any number of homework scores ranging in value from 0 through
Dimas [21]

Answer:

This program is written in Java programming language.

It uses an array to store scores of each test.

And it also validates user input to allow only integers 0 to 10,

Because the program says the average should be calculated by excluding the highest and lowest scores, the average is calculated as follows;

Average = (Sum of all scores - highest - lowest)/(Total number of tests - 2).

The program is as follows (Take note of the comments; they serve as explanation)

import java.util.*;

public class CalcAvg

{

public static void main(String [] args)

{

 Scanner inputt = new Scanner(System.in);

 // Declare number of test as integer

 int numTest;

 numTest = 0;

 boolean  check;

  do

  {

   try

   {

     Scanner input = new Scanner(System.in);

    System.out.print("Enter number of test (1 - 10): ");

    numTest = input.nextInt();

    check = false;

    if(numTest>10 || numTest<0)

     check = true;

   }

   catch(Exception e)

    {

     check = true;

   }

  }

  while(check);

  int [] tests = new int[numTest];

//Accept Input

for(int i =0;i<numTest;i++)

{

System.out.print("Enter Test Score "+(i+1)+": ");

tests[i] = inputt.nextInt();

}

           //Determine highest

           int max = tests[0];

           for (int i = 1; i < numTest; i++)

           {

               if (tests[i] > max)

               {

                   max = tests[i];

               }

           }

           //Determine Lowest

           int least = tests[0];

           for (int i = 1; i < numTest; i++)

           {

               if (tests[i] < least)

               {

                   least = tests[i];

               }

           }

           int sum = 0;

           //Calculate total

           for(int i =0; i< numTest;i++)

           {

               sum += tests[i];

           }

           //Subtract highest and least values

           sum = sum - least - max;

           //Calculate average

           double average = sum / (numTest - 2);

           //Print Average

           System.out.println("Average = "+average);

           //Print Highest

           System.out.println("Highest = "+max);

           //Print Lowest

           System.out.print("Lowest = "+least);

}

}

//End of Program

6 0
3 years ago
What new information, strategies, or techniques have you learned that will increase your technology skills? Explain why its impo
Minchanka [31]

Taking brakes every hour so your eyes don't start to strain.

6 0
3 years ago
Write a loop that reads positive integers from standard input and that terminates when it reads an integer that is not positive.
Paraphin [41]

Answer:

The program to this question as follows:

Program:

#defining variable and assign value

odd=0  

even=0  

i=1  

print('Input 0 after inserting all number: ') #print message

while i>0: #define loop for check inserting and add all number

   i=int(input()) #input value by user end

   if (i< 0): #check value is not positive

       break

   if ((i % 2)==0and(i>0)): #check even number condition

       even=even+i #add even numbers

   if ((i % 2)!=0and(i>0)): #check odd number condition

       odd=odd+i #add odd numbers

print ('Sum of Even number:',even,'and','Sum of Odd number:',odd) #print value

Output:

Input 0 after inserting all number:  

1

2

3

5

7

0

Sum of Even number: 2 and Sum of Odd number: 16

 Explanation:

In the above python program, three variable is defined, that is "even, odd and i", in which "even and odd" variable assign value that is "0", and the variable i is used for inserting elements from user. In the next line a while loop is defined that inserts numbers in variable "i", in this loop, 3 if block is used that can be defined as follows:

  • In first if block variable "i", checks that value is non-positive number if this condition is true, it will break the loop.
  • In second if block this block check even number condition and add in even variable.
  • In third, if block this block check odd number condition and add in odd variable.  

End of the loop we use print function that prints the sum of even numbers and odd numbers.

3 0
2 years ago
Copy the countdown function from Section 5.8 of your textbook. def countdown(n): if n &lt;= 0: print('Blastoff!') else: print(n)
Lapatulllka [165]

Answer:

def countdown(n):

   if n <= 0:

       print('Blastoff!')

   else:

       print(n)

       countdown(n-1)

       

def countup(n):

   if n >= 0:

       print('Blastoff!')

   else:

       print(n)

       countup(n+1)

number = int(input("Enter a number: "))

if number >= 0:

   countdown(number)

elif number < 0:

   countup(number)

<u>Outputs:</u>

Enter a number: 3                                                                                                              

3                                                                                                                              

2                                                                                                                              

1                                                                                                                              

Blastoff!

Enter a number: -3                                                                                                              

-3                                                                                                                              

-2                                                                                                                              

-1                                                                                                                              

Blastoff!

Enter a number: 0

Blastoff!

For the input of zero, the countdown function is called.

Explanation:

Copy the countdown function

Create a function called countup that takes one parameter, n. The function counts up from n to 0. It will print the numbers from n to -1 and when it reaches 0, it will print "Blastoff!".

Ask the user to enter a number

Check if the number is greater than or equal to 0. If it is, call the countdown function. Otherwise, call the countup function.

4 0
2 years ago
John would like to move from the suburbs into the city, but the rent in the city is very high. John has found an apartment he re
maxonik [38]

A list of multiple choices is given;

<span>a)      </span>Purchase a home in the city center instead.

<span>b)      </span>Rent the apartment anyway.

<span>c)       </span>Rent the apartment with a roommate.

<span>d)      </span>Purchase a home in the suburbs instead.


The answer is (C)


John should look for an apartment and share it with a roommate. This will bring down rent expenses to 50% as both John and the roommate will be cost sharing the rent. If the rent expenses go down by 50%, he’ll be able to save an additional 10% and use it for other expenses.

4 0
3 years ago
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