Different codes for access code which are available are: 4000
_ _ _ _
1 2 3 4
1st blank can be filled with the following possibilities, here the conditions are:
1)The first digit cannot be 4
2)The first digit cannot be 0 also since it makes the access code 3 digits hence
From 1 to 9 except 4 there are 8 possible ways to fill that blank
<u>8</u>
2nd blank can be filled with any number between 0 to 9 in 10 possible ways
<u>8</u> <u>10 </u>
3rd blank can be filled with any number between 0 to 9 in 10 possible ways
<u>8</u> <u>10</u> <u>10</u>
4th blank can be filled with any odd numbers between 0 to 10 - 1,3,5,7,9
<u>8</u> <u>10</u> <u>10</u> <u>5</u> = 8 x 10 x 10 x 5 = 4000
Hence to conclude that 4000 available codes are there for the access security card
To know more about permutations and combinations please follow this link
brainly.com/question/1216161
The minimum number of comparisons to find the smallest number from 5 integers is 4.
<h3>How to find the Smallest Integer?</h3>
Let the five numbers be a,b,c,d and e.
Let s be an integer
Comparison 1:
a and b will be compared first and the smaller number of them will be equal to s
Comparison 2:
Now, a smaller number between a and b that is s will be compared with c. Similarly, the smaller number of both numbers will be taken as s in the next comparison.
Comparison 3:
Likewise, s and d will be compared and a smaller number will be taken as s for the next comparison
Comparison 4:
Likewise, s and e will be compared and a smaller number will be taken as s for the next comparison.
After 4th comparison, s will be equal to smallest number of 5 integers.
Thus;
Total comparisons = 4
Therefore, the minimum number of comparisons to find the smallest number from 5 integers is 4.
Read more about Smallest Integer at; brainly.com/question/13329614
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Answer:
The set of input values is called the domain.
C) sound waves do not travel in a vacuum. It's also true
