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Romashka [77]
2 years ago
13

-True-False 18. All types of extinguisher can use in any kinds of fire. - True False ​

Business
1 answer:
Simora [160]2 years ago
5 0

All types of extinguisher can use in any kinds of fire.

  • <em>False</em>

<u>All types of </u><u>extinguishers</u><u> </u><u>cannot</u><u> </u><u>be</u><u> </u><u>used</u><u> </u><u>in</u><u> </u><u>any</u><u> </u><u>kind</u><u> </u><u>of</u><u> </u><u>fire</u><u>.</u><u> </u><u>Let's</u><u> </u><u>understand</u><u> </u><u>this</u><u> </u><u>statement</u><u> </u><u>with</u><u> </u><u>an</u><u> </u><u>example</u><u>.</u><u>.</u><u>.</u>

  • <u>Example</u><u>:</u><u>-</u><u> </u><em>Suppose</em><em> </em><em>that</em><em> </em><em>a</em><em> </em><em>fire</em><em> </em><em>has</em><em> </em><em>taken</em><em> </em><em>place</em><em> </em><em>due</em><em> </em><em>to</em><em> </em><em>some</em><em> </em><em>electrical</em><em> </em><em>issues</em><em>.</em><em> </em><em>This</em><em> </em><em>kind</em><em> </em><em>of</em><em> </em><em>fire</em><em> </em><em>cannot</em><em> </em><em>be</em><em> </em><em>extinguished</em><em> </em><em>by</em><em> </em><em>water</em><em> </em><em>because</em><em> </em><em>water</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>good</em><em> </em><em>conductor</em><em> </em><em>of</em><em> </em><em>electricity</em><em>.</em><em>.</em><em>.</em><em>~</em>
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Tsao Company budgets on an annual basis. The following beginning and ending inventory levels (in units) are plannned for the yea
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Answer:

 a) production units = 450,000

b) Amount of raw materials = 1,010,000.

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The production budget is computed as follows;

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Consider the following work breakdown structure:What is the probability that this project will be completed within 210 days AND
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Answer: 0.8186  

Explanation:

Given that;

activity To    Tm Tp     Te (V)^0.5            v

A         38    50 62    50 4                   16

B         90    99 108    99 3                    9

C         70    80 90    80 3.333333    11.11111

D         19    25 31    25 2                    4

E         91    100 115    101 4                   16

F         62    65 68    65 1                    1

Expected duration Te = (4 × Tm + To + Tp ) / 6

Variance = ( Tp-To/6]²

variance of the critical path = 9+16 =25

SD of the critical path = ( var)^0.5 = 5

probability that the project will be completed within  210 days is given by

z = (210-200) / 5 = 2

which gives probability of 0.97725

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z = (195-200) / 5 = -1

which corresponds to probability of 0.1586

Now required probability that project completes within 210 but before 195 days is given by

0.97725 - 0.1586 = 0.8186  

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