Answer: 0.8186
Explanation:
Given that;
activity To Tm Tp Te (V)^0.5 v
A 38 50 62 50 4 16
B 90 99 108 99 3 9
C 70 80 90 80 3.333333 11.11111
D 19 25 31 25 2 4
E 91 100 115 101 4 16
F 62 65 68 65 1 1
Expected duration Te = (4 × Tm + To + Tp ) / 6
Variance = ( Tp-To/6]²
variance of the critical path = 9+16 =25
SD of the critical path = ( var)^0.5 = 5
probability that the project will be completed within 210 days is given by
z = (210-200) / 5 = 2
which gives probability of 0.97725
Probability that the project will be completed within 195 days
z = (195-200) / 5 = -1
which corresponds to probability of 0.1586
Now required probability that project completes within 210 but before 195 days is given by
0.97725 - 0.1586 = 0.8186