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AleksAgata [21]
3 years ago
14

Consider the following work breakdown structure:What is the probability that this project will be completed within 210 days AND

after 195 days? Time Estimates (days) Activity Precedes Optimistic Most Likely Pessimistic Start A,B,C - - - A D 38 50 62 B E 90 99 108 C E 70 80 90 D E,F 19 25 31 E End 91 100 115 F End 62 65 68
a) 0.815.
b) 0.8413.
c) 0.95.
d) 0.9772.
Business
1 answer:
ella [17]3 years ago
4 0

Answer: 0.8186  

Explanation:

Given that;

activity To    Tm Tp     Te (V)^0.5            v

A         38    50 62    50 4                   16

B         90    99 108    99 3                    9

C         70    80 90    80 3.333333    11.11111

D         19    25 31    25 2                    4

E         91    100 115    101 4                   16

F         62    65 68    65 1                    1

Expected duration Te = (4 × Tm + To + Tp ) / 6

Variance = ( Tp-To/6]²

variance of the critical path = 9+16 =25

SD of the critical path = ( var)^0.5 = 5

probability that the project will be completed within  210 days is given by

z = (210-200) / 5 = 2

which gives probability of 0.97725

Probability that the project will be completed within 195 days

z = (195-200) / 5 = -1

which corresponds to probability of 0.1586

Now required probability that project completes within 210 but before 195 days is given by

0.97725 - 0.1586 = 0.8186  

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Answer:

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Explanation:

In an emergency situation, such as a life-threatening trauma in an emergency room, a supervisor must be direct and assertive.

When there's an emergency situation, this ultimately implies a life and death situation which is typically characterized by having someone being in a very critical and dangerous condition. In order to be able to save such an individual or situations, it is very important and essential to have a direct and assertive supervisor who is in charge or control of the emergency situation and capable of making quick decisions that would most likely salvage the situation.

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On January 1, Year 1, Price Co. issued $190,000 of five-year, 6 percent bonds at 96½. Interest is payable annually on December 3
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Answer:

a) Cash received = $183,350

b) Interest expense = $12,730

c) Carrying value = $186,010

Explanation:

As per the data given in the question,

a) Face value of bond = $190,000

Issued at =0.965

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=$6,650

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6 0
3 years ago
If 7000 dollars is invested in a bank account at an interest rate of 7 per cent per year, Find the amount in the bank after 14 y
Harlamova29_29 [7]

Answer:

1. Interest compounded annually = $18,049.74

2. Interest compounded quarterly = $18,493.77

3. Interest compounded Monthly = $18,598.16

4. Interest compounded continuously = $18,651.19

Explanation:

First let me state the formula for compound interest:

The future value of a certain amount which is compounded is the total amount (Principal + interest) on the amount of money, after compound interests have been applied, and this is shown below:

FV = PV (1+\frac{r}{n} )^{n*t}

where:

FV = Future value

PV = Present value = $7,000

r = interest rate in decimal = 0.07

n = number of compounding periods per year

t = compounding period in years = 14

For interests compounded continuously, the Future value is given as:

FV = PV × e^{r*t}

where

e is a mathematical constant which is = 2.7183

Now to calculate each on the compounding periods one after the other:

1. Interest compounded annually:

here n (number of compounding periods annually) = 1

Therefore,

FV = 7,000 × (1+\frac{0.07}{1})^{14}

FV = 7,000 × 1.07^{14} = $18,049.74

2. Interest compounded quarterly:

here, n = 3 ( there are 4 quarters in a year)

FV = 7,000 × (1+\frac{0.07}{4} )^{4*14}

FV = 7,000 × 1.0175^{56} = $18,493.77

3. Interest compounded Monthly:

here n = 12 ( 12 months in a year)

FV = 7,000 × (1+\frac{0.07}{12} )^{12*14}

FV = 7,000 × 1.005833^{168} = $18,598.16

4. Interests compounded continuously:

FV = PV × e^{0.07 * 14}

FV = 7,000 × 2.66446 = $18,651.19

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