Answer:
The answer is below
Step-by-step explanation:
The corresponding data are missing, which are the following:
Strikes (pre):
29
32
44
34
19
Strikes (post):
51
45
68
92
64
We have to say the difference between the post-pre values of the strike. The d will be the average of the differences between the post and pre values. If Kara is to show improvement, her post-workout attacks should be more than the pre-workout values. Let m be the population mean of the difference:
H0: m = 0 the mean difference in Strikes between post and pre is zero.
H0: m>0, the mean difference in strikes between post and pre is more than zero.
The algebraic expression n/6 represents that the class was divided into 6 equal groups.
Answer:
A. 3.85
Step-by-step explanation:
- If 11 oranges cost $2.35, we could calculate the cost of each of these oranges, simply dividing the total cost ($2.35) between the amount of oranges bougth (11). This will give us the cost of a single orange, that is, the unitary cost=
. - Then, if we want to know the cost of 18 oranges, we just have to multiply the cost of a single orange (0.21) by 18: 0.21x18 = 2.85
Once ur lines are graphed, the solution is where the lines intersect. So by graphing however many equations u have, the point where they intersect is the solution....unless of course u have parallel lines, then there is no solution. And if ur lines are coincident, the same line on top of each other, then there is infinite solutions.
