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Tcecarenko [31]
4 years ago
7

Which problem could be solved by evaluating the expression 4*(-6)

Mathematics
1 answer:
maxonik [38]4 years ago
5 0
-36 one of many possible answers.

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Find the domain y = 7 - 4x / |2x + 5| + 3
murzikaleks [220]

Answer:

Find the domain by finding where the equation is defined. The range is the set of values that correspond with the domain.

Domain: (−∞,∞),{x|x∈R}Range: (−∞,∞),{y|y∈R}

Step-by-step explanation:

4 0
3 years ago
Exercise 2.2.5. Let [[x]] be the greatest integer less than or equal to x. For example, [[π]] = 3 and [[3]] = 3. For each sequen
Debora [2.8K]

Answer:

a) \lim_{n\rightarrow \infty}a_n=0

b) The limit is [[4/3]]=1, that is, \lim_{n\rightarrow \infty}a_n=1

Step-by-step explanation:

The definition of the limit of a sequence (an) is as follows:

\lim_{n\rightarrow \infty}a_n=L (the sequence (an) converges to L) means that given \epsilon>0, there exists some natural number N such that if n≥N, then |a_n-L|

We will use that [[x]] is a increasing function. That is, if x≤y then [[x]]≤[[y]]

a) For all \epsilon>0, take N≥6. Then 1/N ≤1/6 and 5/N ≤ 5/6 < 1. We have that 0<5/N<1, therefore [[5/N]]=0 (0 is the biggest integer less than or equal than x, for any x on the interval 0<x<1)

For n≥N, we have that 1/n ≤ 1/N, hence 0< 5/n ≤ 5/N < 1 . As we discussed above, [[5/n]]=0. Then |a_n|=0, therefore |a_n-0|=|a_n|=0  

b) For all \epsilon>0, take N≥3/4 (any N will do). Then 1/N ≤ 4/3 and 1/4N ≤ 1/3. Note that a_n=[[(12 + 4n)/3n]]=[[1/4n + 4/3]]

For n≥N, we have that 1/4n ≤ 1/4N, hence 1< 4/3< 1/4n +4/3 ≤ 1/4N+4/3 ≤ 5/3 <2.If 1<x<2 then [[x]]=1 , hence a_n=[[1/4n +4/3]]=1  

Then |a_n-1|=|1-1|=0, therefore |a_n-1|=0

4 0
4 years ago
4x+3y=12
77julia77 [94]

Answer:

B, C, F

Step-by-step explanation:

Given:

\left\{\begin{array}{l}4x+3y=12\\ \\2x+3y=-6\end{array}\right.

Subtract the second equation from the first equation:

(4x+3y)-(2x+3y)=12-(-6)\\ \\4x+3y-2x-3y=12+6\\ \\2x=18\\ \\x=9

Option B "The x coordinate of the solution is 9" is ture

Substitute it into the first equation:

4\cdot 9+3y=12\\ \\36+3y=12\\ \\3y=12-36\\ \\3y=-24\\ \\y=-8

Option F "The y coordinate of the solution is -8" is true.

Point (9,-8) is in the IV quadrant, so option C is true.

8 0
3 years ago
Tell which quadrant each of the following points is located in: I, II, III, or IV.
gizmo_the_mogwai [7]

answer:

11.Quadrant 1 10.quadrant II 9. IV 13. IV 12. III 14. III 16: III 17: II 15 I

Step-by-step explanation:

this should help https://socratic.org/questions/what-is-the-order-of-quadrants-in-a-graph  just look at the coordinates x and y if they correspond to which quadrant.

8 0
4 years ago
Two poles, A and B, are 12 meters apart. Pole A is 5 meters high. A rope 20 meters long is tied to the top of pole A and stretch
stepan [7]
The answer should be C, 21. I’ll attach a picture for explanation.
5 0
3 years ago
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