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3 years ago

How to solve for x 6x^2 + 7x +2 = 0

Mathematics

1 answer:

dimulka [17.4K]3 years ago

8 0

Answer: Explanation:

You need to factor this quadratic by playing with multipliers for 6 (1x6, 2x3, 3x2, 6x1) and multipliers for 2 (1x2, 2x1):

(

)

(

)

Now we can solve each term for

−

and

−

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Mittens, a baby kitten, gained 120 grams of weight in 1/3 of a month. If Mittens kept growing at this rate, how much weight woul

dlinn [17]

Answer:

Step-by-step explanation:

Given

A baby kitten, gained 120 grams of weight in 1/3 of a month.

he gain in 1 month

Solution

1/3 month =120gram weight

1 month =120×3

=360 gram is the answer

6 0

3 years ago

PLEASE HELP ME WHAT AM I SUPPOSE TO DO?!

stepladder [879]

Answer:

Step-by-step explanation:

Angle 2= 50

angle 1= 180-50= 130 degrees (linear pair (sum 180))

angle 3= 130 degrees (vertically oposite angles are equal)

angle 6= 130 degrees (alternate interior angles)

angle 5= 180-130= 50 degrees (linear pair)

i hope this helps :)

8 0

3 years ago

drug sniffing dogs must be 95% accurate in their responses because their handlers don't want them to miss durgs and also don't w

GenaCL600 [577]

Answer:

95% Confidence interval: (0.8449,0.9951)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 50

Number of times the dog is right, x = 46

$\hat{p} = \dfrac{x}{n} = \dfrac{46}{50} = 0.92$

95% Confidence interval:

$\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

Putting the values, we get:

$0.92 \pm 1.96(\sqrt{\dfrac{0.92(1-0.92)}{50}})\\\\ = 0.92\pm 0.0751\\\\=(0.8449,0.9951)$

(0.8449,0.9951) is the required 95% confidence interval for the proportion of times the dog will be correct.

7 0

3 years ago

For the region bounded by y=2x, the x-axis, and x=1, determine which of the following is greater: the volume of the solid ge

telo118 [61]

Answer:

The correct answer B) The volumes are equal.

Step-by-step explanation:

The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

$\int\limits^1_0 {(pi)y^{2} } \, dx$

which when evaluated gives 4pi/3.

Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

$\int\limits^2_0 {pi - pix^{2} } \, dy = \int\limits^2_0 {1 - y^{2}/4 } \, dy$

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.

7 0

3 years ago

Each cube in this figure is a -centimeter cube. How many cubes are in the prism? [Type your answer as a number.]

NNADVOKAT [17]

4 Times 3 equals 12 so add 12 three times that equals 36 cubes in the prism.

4 0

3 years ago