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Oksana_A [137]
3 years ago
5

drug sniffing dogs must be 95% accurate in their responses because their handlers don't want them to miss durgs and also don't w

ant false positives. a new dog is being tested and is right in 46 of 50 trials. find the 95% confidence interval for the proportion of times the dog will be correct
Mathematics
1 answer:
GenaCL600 [577]3 years ago
7 0

Answer:

95% Confidence interval:  (0.8449,0.9951)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 50

Number of times the dog is right, x = 46

\hat{p} = \dfrac{x}{n} = \dfrac{46}{50} = 0.92

95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting the values, we get:

0.92 \pm 1.96(\sqrt{\dfrac{0.92(1-0.92)}{50}})\\\\ = 0.92\pm 0.0751\\\\=(0.8449,0.9951)

(0.8449,0.9951) is the required 95% confidence interval for the proportion of times the dog will be correct.

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Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

3 0
3 years ago
Read 2 more answers
Please help! Due tonight<br><br> f(4) if f(x) = 3x - 1
marin [14]
To find f(4), you just replace wherever x is with 4.

f(x) = 3x - 1
⇒ f(4) = 3*(4) - 1
⇒ f(4)= 12-1
⇒ f(4)= 11.

f(4) = 11 is the final answer.

Hope this helps~
5 0
3 years ago
Read 2 more answers
Answer fast please!!!
USPshnik [31]

The correct answer is C. 58

Hope this helps!

3 0
3 years ago
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5. Prove the conditional by proving the contrapositive:
Sunny_sXe [5.5K]

Answer + Step-by-step explanation:

<u>the conditional statement</u> :

For two positive integers n and m,

nm = 4 ⇒  (n = 1  or  m = 1)  or  (n=m= 2)

<u>the contrapositive</u>:

(n ≠ 1  and  m ≠ 1)  and  (n ≠ 2 or m ≠ 2) ⇒ nm ≠ 4

<u>Prove the conditional by proving the contrapositive</u> :

Suppose

m ≠ 1

and m ≠ 2

and n ≠ 1

⇒ nm ≠ 1 × n  and  nm ≠ 2 × n  and n ≠ 1

⇒ nm ≠ 4  (because 4 = 4 × 1 or 4 = 2 × 2)

<u>Conclusion</u>:

The contrapositive is true then conditional is true.

3 0
2 years ago
Need help. and original answer
siniylev [52]

The inequality written in interval notation is therefore -4<x<-1  or (-4, -1)

<h3 /><h3>What are inequalities?</h3>

Inequalities are expressions separated by the mathematical inequalities ≤, ≥, < and >

For instance a < b is a form of inequality.

<h3>What is a number line?</h3>

A number line is a line on which numbers are marked at intervals, used to illustrate simple numerical operations.

From the given number line, we can see that closed circles are on -4 and -1. The inequality written in interval notation is therefore -4<x<-1  or (-4, -1)

Learn more on inequality here: brainly.com/question/24372553

#SPJ1

7 0
2 years ago
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