Answer:
The point C is 12.68 km away from the point A on a bearing of S23.23°W.
Step-by-step explanation:
Given that AB is 50 km and BC is 40 km as shown in the figure.
From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|
=|50 sin 80° - 40 cos 20°|=11.65 km
The length of y-component of AC = |AB cos 80° - BC sin 20°|
=|50 cos 80° - 40 sin 20°|= 5 km
tan
= 5/11.65
=23.23°
AC= 
km
Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.
it is true
Y=1/2 c + 1=81 so the answer is a-True
Answer:
24
Step-by-step explanation:
In this question, you have to solve by plugging in the value to the "k" variable and solve.
Solve:
5(3)^2 - 7(3)
3^2 = 9
5(9) - 7(3)
45 - 7(3)
45 - 21 = 24
Your final answer would be 24.
divide 6000 by 3
6000 / 3 = 2000
so he can do 2000 sq ft per hour
Answer:
r ≤ 29, r-5
The sale price can be compared with the regular price, r-5 ≤ 24
Step-by-step explanation:
Amount to spend = $24
Regular price = r
Sale = $5
Sale Price = r-5
The regular price will be $5, at the max, more than the amount Roopesh has to spend.
The sale price will be $24 or less than that for Roopesh to afford.
Inequality for regular price:
r-5 ≤ 24
r ≤ 29
So, the product Roopesh can afford is $29 or less than that.
What is the unknown? r ≤ 29
Following expression can represent the sale price:
Sale price = r-5
The sale price can be compared with the regular price with the following:
Inequality representing the situation: r-5 ≤ 24
