Answer:
P(Z < 2.37) = 0.9911.
Step-by-step explanation:
We are given that Let z denote a random variable that has a standard normal distribution.
Let Z = a random variable
So, Z ~ Standard Normal(0, 1)
As we know that the standard normal distribution has a mean of 0 and variance equal to 1.
Z =
~ N(0,1)
where,
= mean = 0
= standard deviation = 1
Now, the probability that z has a value less than 2.37 is given by = P(Z < 2.37)
P(Z < 2.37) = P(Z <
) = P(Z < 2.37) = 0.9911
The above probability is calculated by looking at the value of x = 2.37 in the z table which has an area of 0.9911.
48 sq. Units
If I’m wrong I’m truly sorry
It would take 5 hours because you take 3 and divide that by 1.5 & you get 2 so 5 multiplied by 2 is 10. it would take her 30 minutes per page
Answer:
Step-by-step explanation:
Unclear. Did you mean f(x) = 2^(x + 3)? If so, the parentheses are mandatory.
Assuming that f(x) = 2^(x + 3) is correct, then:
a) f(2) = 2^(2 + 3) = 2^5 = 32
b) f'(x) = 2^(x + 3)*(x + 3)' = 2^(x + 3)(1) = 2^(x + 3)
c) f"(x) = 2^(x + 3) (same as in (b)), so that:
f"(12) = 2^15