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algol [13]
2 years ago
14

A scale drawing of a park is 30 inches long and 24 inches wide. On the drawing, 1 inch is equal to 250 feet What are the actual

length and width of the park? Enter the answer in each box.
Mathematics
1 answer:
chubhunter [2.5K]2 years ago
5 0

1 inch equals 250 feet.

Multiply the inches on the map by 250 to get total feet.


30 x 250 = 7,500 feet

24 x 250 = 6,000 feet


The park is 7,500 feet long by 6,000 feet wide

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Jonah runs a bakery, and his most popular item is cinnamon raisin bread. He has two options to purchase raisins.
garri49 [273]

Answer:

C. $0.19/ounce

Step-by-step explanation:

We know that 16 ounces = 1 pound but we have 5 pounds,

So, we do 5 times 16.

We get 80 (ounces)  and we divided ounces by total cost ($15.25)

We get our answer:

$0.19/ounce

3 0
2 years ago
Read 2 more answers
If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2
Oksanka [162]

If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2 times the area of the rectangle, what is the the length and the width

Solution:

Let the length of rectangle=x

Width of rectangle=x/10

Perimeter is 2(Length+Width)

= 2(x+x/10)

Area of Rectangle= Length* Width=x*x/10

As, Perimeter=2(Area)

So,2(x+x/10)=2(x*x/10)

Multiplying the equation with 10, we get,

2(10x+x)=2x²

Adding Like terms, 10x+x=11x

2(11x)=2x^2

22x=2x²

2x²-22x=0

2x(x-11)=0

By Zero Product property, either x=0

or, x-11=0

or, x=11

So, Width=x/10=11/10=1.1

Checking:

So, Perimeter=2(Length +Width)=2(11+1.1)=2*(12.1)=24.2

Area=Length*Width=11*1.1=12.1

Hence, Perimeter= 2 Area

As,24.2=2*12.1=24.2

So, Perimeter=2 Area

So, Answer:Length of Rectangle=11 units

Width of Rectangle=1.1 units

7 0
3 years ago
Read 2 more answers
What is the approximate value of k?
lesya692 [45]

Hello from MrBillDoesMath!

Answer:

5.06

Discussion:

Angle J = 180 - (120 + 40) = 180 - 160 = 20 degrees,

From the law of sines

sin(120)/k = sin(20)/2  =>

sin(120) =  k *  (  sin(20)/2) )                (multiply both sides by "k")

k = sin(120)/  (   sin(20)/2)                    (divide both sides by sin(20)/2)

k =  (0.866) /  ( 0.171) =  5.06


Regards,  

MrB

 P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


6 0
3 years ago
If g (x) = 1/x then [g (x+h) - g (x)] /h
lys-0071 [83]

Answer:

\dfrac{-1}{x(x+h)}, h\ne 0

Step-by-step explanation:

If g(x) = \dfrac{1}{x}, then g(x+h) = \dfrac{1}{x+h}. It follows that

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

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Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

  = \dfrac{-1}{x(x+h)}, h\ne 0

5 0
3 years ago
Evaluate the limit assuming that limx→−5f(x)=17limx→−5f(x)=17 and limx→−5g(x)=22limx→−5g(x)=22. (use symbolic notation and fract
Gemiola [76]

In this question it is given that

\lim_{x->-5}f(x)=17, \lim_{x->-5}g(x)=22

And we have to find the value of the given limit

\lim_{x->-5}(23f(x)+3g(x))

Using properties of limit, first we separate the two functions, that is

23\lim_{x->-5}f(x)+3\lim_{x->-5}g(x)

Substituting the values of the given limit,

23(17)+3(22)=457

3 0
3 years ago
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