-2bc=12-3ab
c=(3ab-12)/(2b)
Answer:
You invested $22,000 in two accounts paying 3% and 5% annual interest, respectively. If the total interest earned for the year was $980, how much was invested at each rate?
Step-by-step explanation:
let x=amt invested at 3% rate of interest.
22000-x=amt invested at 5% rate of interest.
.03x+.05(22000-x)=980
.03x+1100-.05x=980
.02x=120
x=6000
22000-x=16000
amt invested at 3% rate of interest=$6,000
amt invested at 5% rate of interest=$16,000
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Answer:
b=5m+r/m
Step-by-step explanation:
Let's solve for b.
r=(b−5)(m)
Step 1: Flip the equation.
bm−5m=r
Step 2: Add 5m to both sides.
bm−5m+5m=r+5m
bm=5m+r
Step 3: Divide both sides by m.
bm/m=5m+r/m
b=5m+r/m
Answer:
b=5m+r/m
Answer:
18x^4 − 12x^3 + 57x^2 − 28x + 35
Left down, or “Starting at the origin, go 4 spaces to the right and then 1and1/2 spaces up.” This would bring you to the point (4,1and1/2)