Answer:
all vertices on the two lines=60+36=96
Step-by-step explanation:
line a has 6 points and line b has 4 points
now each triangle drawn has on vertices on one line and two vertices on another line:
the line with six points :C(6,2) six points , has two vertices
C(6,2)=6*5/2*1=30/2=15 pairs of points
each pair connected to one point on the other line (4 points)
4*15=60 vertices
now let us consider the two lines on the other line with 4 points:
6c(4,2)=6*((4*3(/2))=6*6=36 vertices
all vertices on the two lines=60+36=96
Answer:
The answer is "Screen B is wider , because 5.3 is greater than 5 and one-third".
Step-by-step explanation:
The mobile display unit must be made similar. Phone A uses a decimal device, and telephone B uses a fraction in this case.
It's easier for you to use. Attempt using the decimal. The width of the phone B fraction could then be translated to decimal width. The computing is:
= 5 cm +
cm
= 5 cm + 0.333cm
= 5.333 cm
It is evident from here that the wider screen of Phone B is than that of Phone A.
Answer:
|AC| = 4.47 units (question attached as image)
Step-by-step explanation:
The question lacks sufficient details. We wil however consider a similar example (image attached) to understand how to solve questions using Pythagoras theorem.
We will calculate for |AC| using Pythagoras theorem, we have:
|AC|² = |AB|² + |BC|²
|AC| = ?, |AB| = 4 units, |BC| = 2 units
|AC|² = 4² + 2² = 16 + 4
|AC|² = 20 ⇒ |AC| = 
|AC| = 4.472135955 ≈ 4.47
|AC| = <u>4.47</u> units
Answer:
The speed at which the water leaves the hole
= 4.21 
The value of diameter of the hole d = 0.112 m = 11.2 cm
Step-by-step explanation:
Given data
Flow rate = 2.5 ×
= 0.0416 ×

Height (h) = 16 m
(a) The speed at which the water leaves the hole :-
Apply bernouli equation for the water tank at point 1 & 2
------ (1)
Since
=
,
& 
Equation (1) becomes

= 
This is the speed at which the water leaves the hole.
Put the values of g & h in the above formula
⇒ 2 g h = 2 × 9.81 × 16 = 17.71
=
= 
= 4.21 
This is the speed at which the water leaves the hole.
(b)Diameter of the hole :-
We know that flow rate Q = A × V

Put the values of Q & V in the above formula we get
A =
× 
A = 9.88 × 
We know that area A = 
⇒
=
× 9.88 × 
⇒
= 0.01258
⇒ d = 0.112 m = 11.2 cm
this is the value of diameter of the hole.