The Formula For Volume Of A Cube Is v = S*S*S Or v = s^3. So:
16*16 = 256. 256*16= 4096. The Volume Is 4096 yds. ^3 Hope This Helps!
Taking the derivative of both sides with respect to
gives
![\dfrac{\mathrm d}{\mathrm dx}[x^2]=\dfrac{\mathrm d}{\mathrm dx}[-2+y+5\cos y]](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Bx%5E2%5D%3D%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5B-2%2By%2B5%5Ccos%20y%5D)
![\implies2x=\dfrac{\mathrm dy}{\mathrm dx}-5\sin y\,\dfrac{\mathrm dy}{\mathrm dx}](https://tex.z-dn.net/?f=%5Cimplies2x%3D%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D-5%5Csin%20y%5C%2C%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D)
![\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x}{1-5\sin y}](https://tex.z-dn.net/?f=%5Cimplies%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%3D%5Cdfrac%7B2x%7D%7B1-5%5Csin%20y%7D)
When
, we have two possible values of
:
![x^2=-2+11+5\cos11\implies x=\pm\sqrt{9+5\cos11}\approx\pm3.004](https://tex.z-dn.net/?f=x%5E2%3D-2%2B11%2B5%5Ccos11%5Cimplies%20x%3D%5Cpm%5Csqrt%7B9%2B5%5Ccos11%7D%5Capprox%5Cpm3.004)
so we have two possible values
.
Answer:
sqrt 8.5
Step-by-step explanation:
apex
Answer:
Yes if Angle 7 and angle 6 are linear pairs in angles created by a straight line that cuts through parallel lines.
Step-by-step explanation:
Remember that two parallel lines that are cut by a transveral will create 8 angles, which will be similar to each other. Making four pairs of congruent angles means that they will be exactly the same angle located in different parts of the system. So if angles 6 and 7 are congruent, and the lines are cut by a transversal, then the lines are parallel.