Answer:
The speed at which the water leaves the hole
= 4.21 
The value of diameter of the hole d = 0.112 m = 11.2 cm
Step-by-step explanation:
Given data
Flow rate = 2.5 ×
= 0.0416 ×

Height (h) = 16 m
(a) The speed at which the water leaves the hole :-
Apply bernouli equation for the water tank at point 1 & 2
------ (1)
Since
=
,
& 
Equation (1) becomes

= 
This is the speed at which the water leaves the hole.
Put the values of g & h in the above formula
⇒ 2 g h = 2 × 9.81 × 16 = 17.71
=
= 
= 4.21 
This is the speed at which the water leaves the hole.
(b)Diameter of the hole :-
We know that flow rate Q = A × V

Put the values of Q & V in the above formula we get
A =
× 
A = 9.88 × 
We know that area A = 
⇒
=
× 9.88 × 
⇒
= 0.01258
⇒ d = 0.112 m = 11.2 cm
this is the value of diameter of the hole.