Option B:
Both n and m must be rational.
Solution:
Given information:
Sum of two numbers, n and m are rational.
<u>To find which statements are true:</u>
Option A: Both n and m may be rational but do not have to be.
It is not true because n and m given is rational.
It have to be rational.
Option B: Both n and m must be rational.
Yes, n and m must be rational then only the sum of numbers are rational.
It is true.
Option C: Both n and m must be irrational.
Sum of irrationals will be sometimes irrational and sometimes can't add.
So it is not true.
Option D: One number is rational and the other is irrational.
Rational and irrational cannot be add.
So it is not true.
Option B is true.
Both n and m must be rational.
The answer is -52 so it would be C
When you see the fraction 33/16, you realize that 33 divided by 16 is 2 remainder 1, so you add the 2 to the original 6, then put the remainder 1 on top of 16 ,which gives you 8 1/16
Answer:
the last one if I'm correct
Step-by-step explanation:
but im not sure I always second guess
