Step-by-step explanation:
Height of ladder = 12ft .
Here perpendicular is height to which it reaches .
<u>When </u><u>angle </u><u>is </u><u>3</u><u>0</u><u>⁰</u><u> </u><u>:</u><u>-</u>
=> sin 30⁰ = H/12
=> ½ = H/12
=> H = 12/2
=> H = 6m ( ans )
<u>When </u><u>Angle </u><u>is </u><u>4</u><u>5</u><u>⁰</u><u> </u><u>:</u><u>-</u><u> </u>
=> sin45⁰ = H/12
=> 1/√2 = H/12
=> H = 6*√2*√2/√2
=> H = 6√2 m ( ans )
<u>When </u><u>angle</u><u> </u><u>is </u><u>6</u><u>0</u><u>⁰</u><u> </u><u>:</u><u>-</u>
=> sin60⁰ = H/12
=> √3/2 = H/12
=> H = 12 *√3/2
=> H = 6√3 ( ans )
hope it helped !
Answer:
a) 229 and 305 days
b) 229 days or less
c) 305 days or more
Step-by-step explanation:
The Empirical Rule(68-95-99.7 rule) states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 267
Standard deviation = 19
(a) Between what values do the lengths of the middle 95% of all pregnancies fall?_____________and___________days
By the Empirical rule, 95% of all pregnancies fall within 2 standard deviations of the mean.
So
267 - 2*19 = 229 days
to
267 + 2*19 = 305 days
(b) How short are the shortest 2.5% of all pregnancies?______days or less
95% of all pregnancies fall within 2 standard deviations of the mean. The other 5% are more than 2 standard deviations from the mean. Since the distribution is symmetric, 2.5% is more than 2 standard deviations below the mean(shortest 2.5%) and 2.5% is more than 2 standard deviations above the mean(longest 2.5%). So
267 - 2*19 = 229 days
c) How long do the longest 2.5% of pregnancies last?________days or more
Explanation in b)
267 + 2*19 = 305 days
The chosen topic is not meant for use with this type of problem. Try the examples below.
[-1,9)u(2,10]
(−1,2)∪(−4,0)
(−1,29)∪(26,50)
Answer:
A) 25
B) 4
C) 0.25
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