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3 years ago

I need help with a problem

Mathematics

1 answer:

stira [4]3 years ago

8 0

I only know question 3

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A restaurant serves custom-made omelets, where guests select meat, cheese, and vegetables to be added to their omelet. There are

kondor19780726 [428]

Answer: The number of different combinations of 2 vegetables are possible = 15 .

Step-by-step explanation:

In Mathematics , the number of combinations of selecting r values out of n values = $^nC_r=\dfrac{n!}{r!(n-r)!}$

Given : Number of available vegetables = 6

Then, the number of different combinations of 2 vegetables are possible will be :

$^6C_2=\dfrac{6!}{2!(6-2)!}=\dfrac{6\times5\times4!}{2\times4!}=15$

Hence , the number of different combinations of 2 vegetables are possible = 15 .

5 0

3 years ago

PLZZ HELP ASAP ILL MAKE U BRAINLIEST

user100 [1]

Translation right down c=

4 0

3 years ago

Read 2 more answers

If a auditorium has 850 seats tickets were sold for 816 of the seats of the seats for what percent of the seats were tickets sol

Sonja [21]

It's 96%

816/850 = 0.96, which is 96%

Hope I helped! ( Smiles )

8 0

3 years ago

A bank sampled its customers to determine the proportion of customers who use their debit card at least once each month. A sampl

Zinaida [17]

Answer:

(0.084,0.396)

Step-by-step explanation:

The 99% confidence interval for the proportion of customers who use debit card monthly can be constructed as

$p-z_{\frac{\alpha }{2}} \sqrt{\frac{pq}{n} }$

$p=\frac{x}{n}$

$p=\frac{12}{50}$

$p=0.24$

$q=1-p=1-0.24=0.76$

$\frac{\alpha }{2} =\frac{\0.01 }{2}=0.005$

$p-z_{\frac{\alpha }{2}} \sqrt{\frac{pq}{n} }$

$0.24-z_{0.005} \sqrt{\frac{0.24*0.76}{50} }$

$0.24-2.58(0.0604)$

$0.24-0.155832$

By rounding to three decimal places we get,

$0.084$

The 99% confidence interval for the proportion of customers who use debit card monthly is (0.084,0.396).

3 0

3 years ago

Bowl A contains 6 apples and 3 mangoes this can be written as, Bowl B contain 8 apples and 2 mangoes this can be written as. Wha

Andrew [12]

Answer:

Bowl B contains 2 apples more than Bowl A and Bowl A contains 1 mango more than Bowl B.

Step-by-step explanation:

Number of apples in Bowl A = 6

Number of mangoes in Bowl B = 8

Difference in apples = 8 - 6 = 2

So, Bowl B contains 2 apples more than Bowl A.

Number of mangoes in Bowl A = 3

Number of mangoes in Bowl B =2

Difference in mangoes = 3 - 2 = 1

So, Bowl A contains 1 mango more than Bowl B.

3 0

3 years ago