I need help with a problem

Determine whether the following function is a one-to-one function. If it is one-to-one, list the inverse function by switching

BartSMP [9]

Answer: An easy way to determine whether a function is a one-to-one function is to use the horizontal line test on the graph of the function. To do this, draw horizontal lines through the graph. If any horizontal line intersects the graph more than once, then the graph does not represent a one-to-one function.

i dont know the exact answer but its a lil sum

Step-by-step explanation:

We know that for any two inverses f(x) = g(y), meaning that if we take f(x) for any x in the domain of f(x), then g(y), where y is the outcome of f(x), should output x. So that is a simple test to see if two functions are inverses.

8 0

3 years ago

Al factorizar el trinomio cuadrado perfecto, obtenemos el siguiente resultado: (que no se como resolver) xd algun pro que sepa r

PolarNik [594]

Answer:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2$

Step-by-step explanation:

Trinomio Cuadrado Perfecto

El producto notable llamado cuadrado de un binomio se expresa como:

$(a-b)^2=a^2-2ab+b^2$

Si se tiene un trinomio, es posible convertirlo en un cuadrado perfecto si cumple con las condiciones impuestas en la fórmula:

* El primer término es un cuadrado perfecto

* El último término es un cuadrado perfecto

* El segundo término es el doble del proudcto de los dos términos del binomio.

Tenemos la expresión:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8$

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

$\displaystyle a=\sqrt{\frac{100}{81}m^8p^{12}q^{16}z^2}$

$\displaystyle a=\frac{10}{9}m^4p^{6}q^{8}z$

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

$\displaystyle b=\sqrt{\frac{1}{49}m^2p^2z^8$

$\displaystyle b=\frac{1}{7}mpz^4$

Nos cercioramos de que el término central es 2ab:

$\displaystyle 2ab=2\frac{10}{9}m^4p^{6}q^{8}z\frac{1}{7}mpz^4$

Operando:

$\displaystyle 2ab=\frac{20}{63}m^5p^7q^8z^5$

Una vez verificado, ahora podemos decir que:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2$

5 0

2 years ago

Help please!! Thank you

Maurinko [17]

Answer:

25 ( A)

pls mark me as BRAINLIEST

stay at home stay safe

and keep rocking

8 0

3 years ago

Read 2 more answers

Question 6

olga nikolaevna [1]

The answer to your question: 5 - 6t
why it’s saying for each number for 6 so what ever number times 6 is t

6 0

2 years ago

9) Gabe has a 40¢-off coupon for any kind of popcorn. He can choose

Vadim26 [7]

Answer:

Per ounce better buy is Happy popcorn.

Step-by-step explanation:

Given that:

Happy popcorn price for 16 ounces = $1.39

Popper popcorn price for 34 ounces = $2.79

Discount coupon present with Gabe = 40 ¢ = $0.40

To find:

Which brand is the better buy per ounce?

Solution:

First of all, let us calculate the price that Gabe has to pay after the discount coupon being applied.

Price for 16 ounces of Happy popcorn after discount = $1.29 - $0.40 = $0.99

Price for 1 ounce of Happy popcorn after discount = $\frac{\$0.99}{16}$ = $0.062

Price for 34 ounces of Popper popcorn after discount = $2.79 - $0.40 = $2.39

Price for 1 ounce of Popper popcorn after discount = $\frac{\$2.39}{34}$ = $0.070

Clearly, per ounce price of Happy popcorn is lesser than that of Popper popcorn.

Therefore per ounce better buy is Happy popcorn.

6 0

2 years ago