Answer:

Step-by-step explanation:
Eqn. 1 ----> 4y = x
Eqn. 2 ----> 5x-10y = -50
(Simplifying eqn.2 further)


(Substituting the value of x from eqn. 1)



Now, substituting the value of y in eqn. 1 ,

Answer:
Step-by-step explanation:
Hello!
X: number of absences per tutorial per student over the past 5 years(percentage)
X≈N(μ;σ²)
You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.
The formula for the CI is:
X[bar] ±
* 
⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.
Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4
X[bar]= 10.41
S= 3.71

[10.41±1.645*
]
[9.26; 11.56]
Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.
I hope this helps!
Answer:
(0,-3)
Step-by-step explanation:
(-3,2) reflected over the line y=1 is (-3,0)
Now rotated 90 degrees over what, and in which direction?
Im going to assume that the rotation is counter clockwise over the origin because that is standard when not mentioned. ¯\_(ツ)_/¯
That would be: (0,-3)
Yw! :D