Solutions of
in the interval from [0,2pi) is
and
.
<u>Step-by-step explanation:</u>
Find all solutions in the interval from [0,2pi)

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⇒ 
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⇒ 
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Cosine General solution is :

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, k is any integer .
At k=0,
⇒
,
At k=1,
⇒ 
⇒ 
Therefore , Solutions of
in the interval from [0,2pi) is
and
.
Answer:
The answer is 
Step-by-step explanation:
In order to determine the answer, we have to know about equation. In an equation, we have variables, some of them depend on the others. If we want to know the value of one variable ( the dependent variable), we have to free it in any side of the equation.
In this case, we want to know the value of "L" variable. So we free that variable to the right side of the equation.

We divide each side by "W":

We simplify the "W" in the right side:

Finally, the solution for "L" is :

1. 20010000
2. 0.0819
3. 137000
4. 0.00060041
The volume of the box is 100 cubic meter.
Step-by step explanation:
Given data:
Length of the box = 10 m
Width of the box = 5 m
Height of the box = 2 m
<u>To find the volume of the box:</u>
Volume of the box = length × width × height
= 10 m × 5 m × 2 m
= 100 cubic meter
Hence the volume of the box is 100 cubic meter.
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