Question

Brainliest? :(

Answer 1

Answer:

$(f\cdot g)(x)=2x^2+10x+12$

$(f-g)(x)=-x-1$

$(f+g)(1)=10$

Step-by-step explanation:

$\tt f(x)=x+3$

$\tt g(x)=2x+4$

$(f\cdot g)(x)=f(x)\cdot g(x)=(x+3)(2x+4)=2x^2+4x+6x+12$

$=2x^2+10x+12$

$(f-g)(x)=f(x)-g(x)=x+3-(2x+4)=x+3-2x-4$

$=-x-1$

$(f+g)(1)=f(1)+g(1)=1+3+2(1)+4$

$=4+2+4=10$

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