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2 years ago

Find the distance between the two points on a coordinate A(5, 1) B(-3,- 3)

Mathematics

2 answers:

julsineya [31]2 years ago

6 0

$\tt AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$\tt AB=\sqrt{(-3-5)^2+(-3-1)^2}\\\\AB=\sqrt{-8^2+-4^2}\\\\AB=\sqrt{80}=4\sqrt{5}$

Igoryamba2 years ago

4 0

Step-by-step explanation:

hope this help uhh ...

have a good day.

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Triangle DNO has vertices at D(5, 8), N(– 3, 10), and O(– 3, 6). If vertex D is translated 4 units to the right, the best name f

prisoha [69]

Using distance between two points to find the lengths of the edges of the triangle, the correct option is:

b. Isosceles

The distance between two points, $(x_1,y_1)$ and $(x_2,y_2)$ , is given by:

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Vertex D is translated 4 units to the right is (9,8).

The lengths of the edges are:

$DN = \sqrt{(9 - (-3))^2 + (8 - 10)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}$

$DO = \sqrt{(9 - (-3))^2 + (8 - 6)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}$

$NO = \sqrt{(-3 - (-3))^2 + (10 - 6)^2} = \sqrt{0^2 + 4^2} = 4$

Two edges of the same length, hence, it is an isosceles triangle, given by option b.

You can learn more about distance between two points at brainly.com/question/18345417

6 0

2 years ago

7+(-3)+(-5)-10 how do i simplify

4vir4ik [10]

Answer:

-11

Step-by-step explanation:

7 - 3 - 5 - 10

4 - 5 - 10

- 1 - 10

-11

8 0

3 years ago

HELP PLEASEE!!!!

ss7ja [257]

Answer:

See below ~

Step-by-step explanation:

$\textsf {Each of the steps has been reasoned below :}$

$\implies \textsf {3x - 2 = 4 (Given)}$

$\implies \textsf {3x = 6 (Addition Property of Equality)}$

$\implies \textsf {x = 2 (Division Property of Equality)}$

$\textsf {In the second step, the property has been applied}\\\textsf {by adding 2 to each side of the equation.}$

$\textsf {In the third step, the property has been applied by dividing 3 on each side.}$

3 0

2 years ago

Read 2 more answers

Can anybody solve this? If you will get it right I will mark you brainiest.

ikadub [295]

Answer:

The answer is one.

Step-by-step explanation:

I'm not exactly sure if I'm right , so sorry, if it's wrong

4 0

3 years ago

Read 2 more answers

PLS HELP ME WITH THIS!!!!!! HOW DID THEY GET 80ft^2

noname [10]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Determine the surface area of the right square pyramid.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

The formula for finding the surface area of a right square pyramid is ⇨ b² + 2bl, where

b = base of the right square pyramid
l = slant height of the right square pyramid.

In the given figure,

base (b) = 4 ft.
slant height (l) = 8 ft.

Now, let's substitute the values of b & l in the formula & solve it :-

$\sf \: {b}^{2} + 2bl \\ = \sf \: {4}^{2} + 2 \times 4 \times 8 \\ = \sf \: 16 + 8 \times 8 \\ = \sf \: 16 + 64 \\ = \huge\boxed{\boxed{ \bf 80 \: ft ^{2} }}$

So, the surface area of the right square pyramid is 80 ft².

7 0

3 years ago