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2 years ago

Find the distance between the two points on a coordinate A(5, 1) B(-3,- 3)

Mathematics

2 answers:

julsineya [31]2 years ago

6 0

$\tt AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$\tt AB=\sqrt{(-3-5)^2+(-3-1)^2}\\\\AB=\sqrt{-8^2+-4^2}\\\\AB=\sqrt{80}=4\sqrt{5}$

Igoryamba2 years ago

4 0

Step-by-step explanation:

hope this help uhh ...

have a good day.

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Need some help! Graph the equations y=3x-5 and x+3y=6 on the same xy-plane. What is significant about these two lines? (Explain

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Read 2 more answers

How many times does 5.4 go into 60 if it starts at -18?

photoshop1234 [79]

Answer:

14 $\frac{4}{9}$

Step-by-step explanation:

starting at -18 you must add 5.4 until you reach 60

-18 + 5.4 = -12.6 once (1)

-12.6 + 5.4 = -7.2 twice (2)

-7.2 + 5.4 = -1.8 thrice (3)

-1.8 + 5.4 = 3.6 fourth (4)

3.6 + 5.4 = 9 fifth (5)

9 + 5.4 = 14.4 sixth (6)

14.4 + 5.4 = 19.8 seventh (7)

19.8 + 5.4 = 25.2 eighth (8)

25.2 + 5.4 = 30.6 ninth (9)

30.6 + 5.4 = 36 tenth (10)

36 + 5.4 = 41.4 eleventh (11)

41.4 + 5.4 = 46.8 twelth (12)

46.8 + 5.4 = 52.2 thirteenth (13)

52.2 + 5.4 = 57.6 fourteenth (14)

since 57.6 + 5.4 is over 60, we need to find the difference in how much we need

57.6 - 60 = -2.4

we need 2.4 so subtract by 5.4

5.4 - 2.4 = 3

therefore we should divide

$\frac{2.4}{5.4}$ = 14.444...

which means it goes into 60 (starting at -18) 14.444... repeating times

another way to find the answer is

add 18 + 60

18 + 60 = 78

78/5.4 = 14.444... repeating or 14 $\frac{4}{9}$

hope this helps:)

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