Problem: 2x^2+3x-9
For a polynomial of the form, ax^2+bx+c rewrite the middle term as the sum of two terms whose product a·c=2·-9=-18 and whose sum is b=3.
Factor 3 out of 3x
2x^2+3(x)-9
Rewrite 3 as -3 plus 6.
2x^2+(-3+6)x-9
Apply the distributive property
2x^2(-3x+6x)-9
Remove the parentheses
2x^2-3x+6x-9
Factor out the greatest common factor from each group
Group the first two terms and the last two terms
(2x^2-3x) (6x-9)
Factor out the greatest common factor in each group.
x(2x-3)+3(2x-3)
Factor the polynomial by factoring out the greatest common factor, 2x-3
(x+3) (2x-3). So, the quotient is 2x-3
Each week he earned 200 + 8% of his sales....
sales = 3200
200 + 0.08(3200) = 200 + 256 = 456 <==
Answer:
10.4% or 13/125
Step-by-step explanation:
5 perfect squares in the set of numbers
13 odd numbers
(5/25) x (13/25) = 0.104
0.104 x 100 = 10.4%
i hope its right
Answer: 17.60 is a terming decimal 25.60 is a repeating decimal i dont know the rest sorry
Step-by-step explanation:
