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2 years ago

How many full hours will it take for the number of amoeba to reach 1 million

Mathematics

1 answer:

dimulka [17.4K]2 years ago

5 0

Answer:

250,000 hours

Step-by-step explanation:

if 2 amoeba takes half an hour then 4 amoeba will take 1 full hour then use 4 to divide 1 million.

If u were to use 2 amoeba to half an hour you will have to divide 1 million into two which is 500,00

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"find the reduction formula for the integral" sin^n(18x)

dexar [7]

Let

$I(n,a)=\displaystyle\int\sin^nax\,\mathrm dx$
For demonstration on how to tackle this sort of problem, I'll only work through the case where $n$ is odd. We can write

$\displaystyle\int\sin^nax\,\mathrm dx=\int\sin^{n-2}ax\sin^2ax\,\mathrm dx=\int\sin^{n-2}ax(1-\cos^2ax)\,\mathrm dx$
$\implies I(n,a)=I(n-2,a)-\displaystyle\int\sin^{n-2}ax\cos^2ax\,\mathrm dx$

For the remaining integral, we can integrate by parts, taking

$u=\sin^{n-3}ax\implies\mathrm du=a(n-3)\sin^{n-4}ax\cos ax\,\mathrm dx$ $\mathrm dv=\sin ax\cos^2ax\,\mathrm dx\implies v=-\dfrac1{3a}\cos^3ax$

$\implies\displaystyle\int\sin^{n-2}ax\cos^2ax\,\mathrm dx=-\dfrac1{3a}\sin^{n-3}ax\cos^3ax+\dfrac{a(n-3)}{3a}\int\sin^{n-4}ax\cos^4ax\,\mathrm dx$

For this next integral, we rewrite the integrand

$\sin^{n-4}ax\cos^4ax=\sin^{n-4}ax(1-\sin^2ax)^2=\sin^{n-4}ax-2\sin^{n-2}ax+\sin^nax$
$\implies\displaystyle\int\sin^{n-4}ax\cos^4ax\,\mathrm dx=I(n-4,a)-2I(n-2,a)+I(n,a)$

So putting everything together, we found

$I(n,a)=I(n-2,a)-\displaystyle\int\sin^{n-2}ax\cos^2ax\,\mathrm dx$
$I(n,a)=I(n-2,a)-\left(-\dfrac1{3a}\sin^{n-3}ax\cos^3ax+\dfrac{n-3}3\displaystyle\int\sin^{n-4}ax\cos^4ax\,\mathrm dx\right)$
$I(n,a)=I(n-2,a)-\dfrac{n-3}3\bigg(I(n-4,a)-2I(n-2,a)+I(n,a)\bigg)+\dfrac1{3a}\sin^{n-3}ax\cos^3ax$
$\dfrac n3I(n,a)=\dfrac{2n-3}3I(n-2,a)-\dfrac{n-3}3I(n-4,a)+\dfrac1{3a}\sin^{n-3}ax\cos^3ax$

$\implies I(n,a)=\dfrac{2n-3}nI(n-2,a)-\dfrac{n-3}nI(n-4,a)+\dfrac1{na}\sin^{n-3}ax\cos^3ax$

7 0

3 years ago

What is a number that multiplies a variable in a term ?

kirill [66]

<h3>A number that multiplies a variable in a term is known as a coefficient.</h3>

Given the term: 6x^3, we can identify three parts:

The coefficient, 6, is the constant that is being multiplied by the variable.

The variable, x, is a number with an unknown value, or with multiple potential values.

The exponent, 3, is the power with which the variable is being raised to.

7 0

2 years ago

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A number from 8 to 15 is drawn from a bag at random. What is the theoretical probability of drawing the number 12?

tamaranim1 [39]

It would be 15 percent

4 0

3 years ago

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3. Find the values of the variables and the lengths of the sides of this kite.

Kazeer [188]

Answer:

So, the correct option is A. x = 9, y = 14 , Sides are 11 and 20

Step-by-step explanation:

P.S - the exact question is -

As given in the question ,

Side AB = Side AD

⇒y - 3 = x + 2

⇒y - x = 2 + 3 = 5

⇒y - x = 5 .........(1)

Also, given

Side BC = Side CD

⇒2x + 2 = x + 11

⇒2x - x = 11 - 2

⇒x = 9

∴ equation (1) becomes

y - 9 = 5

⇒y = 5 + 9 = 14

⇒y = 14

∴ we get

x = 9, y = 14

Now,

as given ,

Side AB = y - 3

⇒ AB = 14 - 3 = 11

Side BC = 2x + 2

⇒ BC = 2(9) + 2 = 18 + 2 = 20

Side CD = x + 11

⇒ CD = 9 + 11 = 20

Side DA = x + 2

⇒DA = 9 + 2 = 11

∴ we get

The sides are 11 and 20

So,

The correct option is A. x = 9, y = 14 , Sides are 11 and 20

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2 years ago

Can you please help me with this question? thank you!!!

Rufina [12.5K]

Answer:

The top box in the middle, should be 15.

The bottom box on the left should be 1.5

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3 years ago

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