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Anestetic [448]
3 years ago
11

Find the roots of the quadratic equation 2x^2-x-4 =0

Mathematics
1 answer:
professor190 [17]3 years ago
7 0

Answer:

I hope it will help you...

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Five thousand two hundred sixty-seven. standard form
Sati [7]

Answer:

5,267

Step-by-step explanation:

Five thousand: 5,000

Two hundred: 200

Sixty: 60

Seven: 7

Put them together: 5,267

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A. How much carpet does Erin need?
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A. she needs 81sq ft

b. 202.5$
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What’s is 4C? Help me out
sveticcg [70]

A would be the correct answer hope this helps

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2 years ago
Solve -3(x+5) = -9 solve
Bumek [7]
-3(x + 5) = -9
-3x + -15 = -9
-3x - 15 = -9
-3x - 15 + 15 = -9 + 15 (we added 15 to both sides of the equation because now, the 15 on the left side cancels out).
-3x = 6
-3x/-3 = 6/-3
X = -2
So, in conclusion, X is equal to -2.
5 0
2 years ago
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Given a rectangle with an area of 20 square units, if the width is x units and the length is x + 1 units, what is the difference
ollegr [7]

Answer: 1unit.

Step-by-step explanation:

Area of the rectangle

A = length × width

Since the area = 20 and the width is x and the length is x + 1.

We now substitute for the values in the above formula and solve for x

20 = x × x + 1

20 = x( x + 1 ), we now open

20 = x² + x , then re arrange.

x² + x - 20 = 0, this is a quadratic equation.we solve for x using quadratic means

Here, I am going to solve using factorization by grouping

x² + x - 20 = 0

x² + 5x - 4x - 20 = 0

x( x + 5 ) - 4( x + 5 ) = 0

( x + 5 )( x - 4 ). = 0

Therefore, the solution for x will be

x = -5 or 4, but x can not be -5 ( negative), so x = 4.

Now the difference between width and the length can easily be calculated from the above,

Width = 4 (x) , and length = 5 (4 + 1),

Now difference will be

5 - 4 = 1unit.

5 0
3 years ago
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