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-Dominant- [34]
3 years ago
5

Graph Quadrilateral ABCD if A(-4,1), B(1,5), C(4,1), D(-3,-4).

Mathematics
1 answer:
BartSMP [9]3 years ago
7 0

Answer: 64.5

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Can someone show me how to factor this please?
Alex_Xolod [135]

Answer:

\displaystyle \theta = \left\{\frac{7\pi}{6}, \, \frac{3\pi}{2}, \frac{11\pi}{6}\right\}

Step-by-step explanation:

We want to solve the equation:

2\sin ^2 \theta + 3\sin \theta + 1 = 0

In the interval [0, 2π).

Notice that this is in quadratic form. Namely, by letting u = sin(θ), we acquire:

\displaystyle 2u^2 + 3u + 1 = 0

Factor:

\displaystyle (2u+1)(u+1) = 0

By the Zero Product Property:

\displaystyle 2u + 1 = 0\text{ or } u + 1 = 0

Solve for each case:

\displaystyle u = -\frac{1}{2} \text{ or } u = -1

Back-substitute:

\displaystyle \sin \theta = -\frac{1}{2} \text{ or } \sin \theta =-1

Use the Unit Circle. Hence, our three solutions in the interval [0, 2π) are:

\displaystyle \theta = \left\{\frac{7\pi}{6}, \, \frac{3\pi}{2}, \frac{11\pi}{6}\right\}

8 0
3 years ago
Aleksandra started studying how the number of branches in her tree grows over time. Every 1.5 years, the number of branches incr
vova2212 [387]

Answer:

N = 52 * (9/7)^(t/1.5)

Step-by-step explanation:

This problem can be modelated as an exponencial problem, using the formula:

N = Po * (1+r)^(t/1.5)

Where P is the final value, Po is the inicial value, r is the rate and t is the amount of time.

In our case, we have that N is the final number of branches after t years, Po = 52 branches, r = 2/7 and t is the number of years since the beginning (in the formula we divide by 1.5 because the rate is defined for 1.5 years)

Then, we have that:

N = 52 * (1 + 2/7)^(t/1.5)

N = 52 * (9/7)^(t/1.5)

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3 years ago
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3/5 1/6 3/7 2/5
------------------------
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3 years ago
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andreyandreev [35.5K]

Answer:

20??? wow I feel stupid I forgot how to do everything

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3 years ago
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