Option B:
Both n and m must be rational.
Solution:
Given information:
Sum of two numbers, n and m are rational.
<u>To find which statements are true:</u>
Option A: Both n and m may be rational but do not have to be.
It is not true because n and m given is rational.
It have to be rational.
Option B: Both n and m must be rational.
Yes, n and m must be rational then only the sum of numbers are rational.
It is true.
Option C: Both n and m must be irrational.
Sum of irrationals will be sometimes irrational and sometimes can't add.
So it is not true.
Option D: One number is rational and the other is irrational.
Rational and irrational cannot be add.
So it is not true.
Option B is true.
Both n and m must be rational.
The intersection of two sets A and B is defined as the set composed by the elements appearing in both A and B.
So, the intersection is
Because all the other numbers do not belong to both sets:
- 2, 3 and 7 belong to A alone
- 13, 15 and 17 belong to B alone
- 5 and 11 belong to both A and B
Answer: -2
In order to find the slope of this equation you must put it into slope form which is y=mx+b
Solved: y= -2+5
M is the slope
Pretty Sure it’s y=x+(-.8) haven’t done algebra in a bit. Sorry if wrong. :/
