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Ilya [14]
2 years ago
7

Find an angle in each quadrant with a common reference angle with 216°, from 0°=0<360°

Mathematics
1 answer:
Naddik [55]2 years ago
7 0

Answer:

Quadrant 1: 36°

Quadrant 2: 144°

Quadrant 3 (Given): 216°

Quadrant 4: 324°

Step-by-step explanation:

A 216° angle in standard position has its terminal side in quadrant 3 since 216° is between 180° and 270°.

216° - 180° = 36°

The reference angle for 216° is 36°

Quadrant 1: 36°

Quadrant 2: 180° - 36° = 144°

Quadrant 3 (Given): 216°

Quadrant 4: 360° - 36° = 324°

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garik1379 [7]

10d+ 25q+5n= 805

D= n+8

Q= n+ 5



10d+ 25q+5n= 805

10(n+8)+25(n+5)+5n=805

10n+80+25n+125+5n=805

40n+205=805

40n=805-205

40n= 600

N=600/40

N= 15


D= n+8

D= 15+8

D= 23


Q=n+5

Q=15+5

Q=20


So 15 nickels ,23 dimes and 20quarters .


To check

15(0.05)= $0.75

23(0.10)=$2.30

20(0.25)=$5.00


Add it

5.00+2.30+0.75=8.05

7.30+.75=8.05

8.05=8.05

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3 years ago
Simplify the following surd expressions
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Answer:

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Step-by-step explanation:

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<h3>adding or subtracting with redical experience is nothing but algebraic addition or subtraction</h3><h3>let's solve:</h3>

a)7 \sqrt{3}  - 2 \sqrt{3}  +  \sqrt{3}  - 3\sqrt{3}  \\ 8 \sqrt{3}  - 5 \sqrt{3}  \\ 3 \sqrt{3}

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Answer:

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Semmy [17]

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Indicate the equation of the given line in standard form. The line with slope 9/7 and containing the midpoint of the segment who
professor190 [17]

Given parameters:

Coordinates of end points =  (2, -3) and (-6,5).​

 Slope of line  = \frac{9}{7}

Unknown:

Equation of the line with the given slope = ?

Solution:

Let us find the coordinates of the mid-point of the line given.

   Since the end points are (2, -3) and (-6,5);

   Midpoint;

            x, y = \frac{x_{1} + x_{2} }{2} , \frac{y_{1} + y_{2} }{2}  

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The coordinate of the mid point = -2,1

Equation of a line is;

                  y = mx + c

x and y are the coordinates

     m is the slope

     c is the y intercept

We need to find c in order to fully develop our equation;

             y = mx + c

              y = 1 , x = -2 and m = \frac{9}{7}

So,

           1 = \frac{9}{7} x (-2) + c

            c  = 1 + \frac{18}{7}   = \frac{25}{7}

Now, the equation of the line is;

              y = -2x + \frac{25}{7}  

Multiply through by 7,

            7y = -14x + 25

The equation of the line is 7y = -14x + 25

3 0
3 years ago
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