All categories

3 years ago

Please help me with answer ASAP

Mathematics

1 answer:

german3 years ago

8 0

Answer:

use the web site

Step-by-step explanation:

Math w ay .c om

it gives all the answer to any question you have

You might be interested in

An experiment involves selecting a random sample of 256 middle managers at random for study. one item of interest is their mean

Nitella [24]

The standard error of the mean is 128.125.

The formula for standard error is:

$\sigma_M=\frac{\sigma}{\sqrt{N}}$

With our information, we have:

$\sigma_M=\frac{2050}{\sqrt{256}}=128.125.$

7 0

3 years ago

Alice is a chinese-american student. She needs student aid to

Ad libitum [116K]

She needs aid with translation.

4 0

3 years ago

In the school band, there are 4 trumpet players and F flute players.The total number of trumpet and flute players is 12. Are the

Annette [7]

Yes there are 8 flute players
The equation is
4+F=12
Subtract 4 from both sides you have F=8

8 0

3 years ago

If f(x)=x^3-12x^2+35x-24f(x)=x 3 −12x 2 +35x−24 and f(8)=0f(8)=0, then find all of the zeros of f(x)f(x) algebraically.

Neporo4naja [7]

Answer:

The zeros of f(x) are: (x - 1), (x - 3) and (x - 8)

Step-by-step explanation:

Given

$f(x)=x^3-12x^2+35x-24$

$f(8) = 0$

Required

Find all zeros of the f(x)

If $f(8) = 0$ then:

$x = 8$

And $x - 8$ is a factor

Divide f(x) by x - 8

$\frac{f(x)}{x - 8} = \frac{x^3-12x^2+35x-24}{x - 8}$

Expand the numerator

$\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 -8x^2 + 3x + 32x - 24}{x - 8}$

Rewrite as:

$\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 + 3x - 8x^2 +32x - 24}{x - 8}$

Factorize

$\frac{f(x)}{x - 8} = \frac{(x^2 - 4x + 3)(x - 8)}{x - 8}$

Expand

$\frac{f(x)}{x - 8} = \frac{(x^2 -x - 3x + 3)(x - 8)}{x - 8}$

Factorize

$\frac{f(x)}{x - 8} = \frac{(x - 1)(x - 3)(x - 8)}{x - 8}$

$\frac{f(x)}{x - 8} = (x - 1)(x - 3)$

Multiply both sides by x - 8

$f(x) = (x - 1)(x - 3)(x - 8)$

<em>Hence, the zeros of f(x) are: (x - 1), (x - 3) and (x - 8)</em>

7 0

3 years ago

Find the equation of the tangent line to the graph of f(a) = sec(a) at the point (0, 1).

Paladinen [302]

Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0

y = mx + c
1 = 0(0) + c
c = 1

Therefore, required equation is
y = 1.

5 0

3 years ago