Which of the following correctly shows a prairie food chain?

Biology

1 answer:

Ivenika [448]2 years ago

5 0

The first one does.

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The % of children with webbed digits is $50$ %

Explanation:

Given -

Syndactyly or webbed digits are due to the presence of a dominant allele (S). Then the allele for normal digits would be represented by allele "s"

A normal man with normal digits and genotype "ss" marries a woman with webbed digits and has a hetrozygous genotype i.e "Ss"

If we cross Ss and ss , then the following offspring are produced -

Ss * ss

Ss, Ss, ss, ss

Out of four 2 offspring with genotype ss have normal digits and remaining two offspring with genotype "Ss" have webbed digits. Thus, the % of children with webbed digits is $50$ %

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