2(w-5)=6. ...................
The value of p+q = 403,For the given complex number a+bi and
where p and q are co-primes
F(z)= (a+ib)z⇒this is equidistant from "0" and "z"
Given modulus of complex number (a+ib) = 10 ;
p and q ∈Z
G.C.D of ( p and q)=1
(a+ib)z equidistant from "0" and "z"


p = 399 and q= 4
p+q= 399+4
p+q=403
Hence the value of p+q = 403
Complete question:A function f is defined on the complex number by f (z) = (a + bi)z, where 'a' and 'b' are positive numbers. This function has the property that the image of each point in the complex plane is equidistant from that point and the origin. Given that |a+bi|=8 and that
where p and q are coprime. Find the value of (p+q)
Learn more about complex numbers here:
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Answer:
y= −2/3x+−20/3
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Answer:
3
Step-by-step explanation:
3 to get to 15, multiply by 3, same for other sides.
To factor this collect the like terms..2y would go with -7y to make -5y etc. Then factor the expression by factoring out 9 Your final answer should be 9(1-y+x^2)
If you need to simplify this calculate the sum or difference between numbers (3-1+7=9)
Your final answer for this should be 9-9y+9x^2
Hope this helps!