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2 years ago

Two nimbers have a product of 90 and a sum of 19. What are the two numbers?

Mathematics

1 answer:

bulgar [2K]2 years ago

6 0

Answer:

9 + 10 = 19 product is 9 x 10 = 90 9^2 + 10^2 = 181

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What is the measure of WUX in Circle V ?

Alja [10]

Answer:

$arc\ WUX=120^o$

Step-by-step explanation:

<u><em>The complete question is:</em></u>

In circle V, angle WXZ measures 30°. Line segments WV, XV, ZV, and YV are radii of circle V. Circle V is shown. Line segments W V, X V, Z V, and Y V are radii. Lines are drawn from point W to point X and from point Z to point Y to form secants. Point U is on the circle between points W and X. What is the measure of Arc W U X in circle V?

The picture of the question in the attached figure

step 1

Find the measure of angle XWV

we know that

The triangle VWX is an isosceles triangle, because has two equal sides (VX=VW)

we have

$m\angle WXZ=30^o\\m\angle WXV=m\angle WXZ$

$m\angle WXV=30^o$

Remember that an isosceles triangle has two equal interior angles

step 2

Find the measure of angle WVX

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

$m\angle\ WVX+m\angle XWV+m\angle WXV=180^o$

substitute the given values

$m\angle WVX+30^o+30^o=180^o\\m\angle WVX=180^o-60^o=120^o$

step 3

Find the measure of arc WUX

we know that

$arc\ WUX=m\angle WVX$ ----> by central angle

we have

$m\angle WVX=120^o$

therefore

$arc\ WUX=120^o$

4 0

3 years ago

Andrew is about to leave for school. If he walks at a speed of 50 meters per minute, he will arrive 3 minutes after the bell rin

Mariana [72]

Answer:

The answer is: 13 minutes

Step-by-step explanation:

First Let us form equations with the statements in the two scenario

$time=\frac{distance}{speed}$

Let the time in which the bell rings be 'x'

1. If Andrew walks (50 meters/minute), he arrives 3 minutes after the bell rings. Therefore the time of arrival at this speed = (3 + x) minutes

$3 + x =\frac{distance}{50}\\distance = 50(3+x) - - - - - (1)$

2. If Andrew runs (80 meters/minute), he arrives 3 minutes before the bell rings. Therefore the time taken to travel the distance = (x - 3) minutes

$x - 3 = \frac{distance}{80} \\distance = 80(x-3) - - - - - (2)$

In both cases, the same distance is travelled, therefore, equation (1) = equation (2)

$50(3+x)=80(x-3)$

$150 +50x=80x-240\\$

Next, collecting like terms:

$150 + 240 = 80x - 50x\\390 = 30x\\30x = 390\\$

dividing both sides by 3:

x = 390÷30 = 13

∴ x = 13 minutes

7 0

2 years ago

Jasmine’s race time was 34.287 minutes.round her race time to the nearest 10th of a minute

amm1812

Hi!

34.287 rounded to the nearest tenth is 34.290

This is because 7 is greater than 5, so we would round it to the cloest tenth that is slightly higher than 7. =)

7 0

2 years ago

Read 2 more answers

PLEASE HELP!!!!!!! Will mark brainlest!!!

pochemuha

Answer:

Step-by-step explanation:

78-90 = 12

4 0

2 years ago

Which solution is the best estimate to the system of equations?

Alexeev081 [22]