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3 years ago

(01.01 LC)Which two temperatures have a sum of 0 degrees Celsius?

Mathematics

2 answers:

STatiana [176]3 years ago

6 0

Answer:

its 4 degrees celsius and -4 degrees celcius

Step-by-step explanation:

emmasim [6.3K]3 years ago

4 0

The second option is the correct cjoice

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HELPPP PLEASEE 10 POINTS

Sladkaya [172]

Answer:

I got 31,529.8281

Step-by-step explanation:

I just replaced minimum with one(if i can do that).

If it's not right sorry.

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

Which expressions are equivalent to (5g+3h+4) . 2

Elza [17]

Answer:

2(5g+3h+4)

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Please that is the answer

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3 years ago

What is the surface area?

frosja888 [35]

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3 years ago

How do you factor 125-x^3?

xz_007 [3.2K]

Step-by-step explanation:

We have

$125 - x {}^{3}$

First, 125 is a perfect cube because

$5 \times 5 \times 5 = 125$

and

x^3 is a perfect cube because

$x \times x \times x = x {}^{3}$

so we can use the difference of cubes identity

$( {x}^{3} - {y}^{3} ) = (x - y)( {x}^{2} + xy + {y}^{2} )$

Let say we have two perfect cubes:

64 because 8×8×8=64

and 27 because 3×3×3=27 and let subtract

$64 - 27$

we know that

$64 - 27 = 37$

but using the difference of cubes identity we should get the same thing.

Remeber cube root of 64 is 4 and cube root of 27 is 3 so we have

$(4 - 3)( {4}^{2} + 4(3) + 3 {}^{2} )$

$1(16 + 12 + 9) = 1(37) = 37$

So the difference of cubes works for real numbers. This is a good way to help remeber the identity using real numbers.

Back on to the topic,

we know that 5 is cube root of 125 and x is the cube root of x^3 so we have

$(5 - x)( {5}^{2} + 5x + {x}^{2} ) =$

$(5 - x)(25 + 5x + {x}^{2} )$

3 0

3 years ago

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