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aivan3 [116]
3 years ago
5

Can someone plz help meeee!! :(

Mathematics
2 answers:
Sedbober [7]3 years ago
7 0

Answer:

64

Step-by-step explanation:

It is going up by 6

Harman [31]3 years ago
3 0
The answer is 64, since it increases by 6
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2/3 divide by 4/5? ​
Alenkasestr [34]

Answer:

\frac{5}{6}

Step-by-step explanation:

  \frac{2}{3}                ÷                 \frac{4}{5}

  ↓               ↓                 ↓  

leave it   change it   turn it over

  \frac{2}{3}                ×                  \frac{5}{4}

now solve it

\frac{2}{3} × \frac{5}{4} = \frac{10}{12}

now simplify it

\frac{10}{12} = \frac{5}{6}

4 0
3 years ago
Someone plz help on # 15 (idk what to do) :/
aleksklad [387]

Answer:

2x-5= -20

move -5 to the other side

sign changes from -5 to 5

2x-5+5= -20+5

2x= -15

divide by 2 for both sides

2x/2= -15/2

cross out 2 and 2, divide by 2 and 2 and then becomes x

x= -15/2

4 0
3 years ago
at video shack movie rentals cost $3.99 each. the cost of renting three movies and one video game is $.11 less than the cost of
damaskus [11]
x-\ cost\ of\ renting\ video\ game\\
y-\ cost\ of\ tenting\ movie\\\\
3y+1x+11=5x\\
y=3,99\\\\
3*3,99+x+11=5x\\
11,97+x+11=5x\ \ \ | subtract\ x\\
22,97=4x\ \ \ | divide\ by\ 4\\
x=5,7425\$\\\\
For\ renting\ video\ game\ you\ will\ pay\ 5,7425\$.
4 0
4 years ago
All of these statements are true EXCEPT which one? <br>A.​
Zolol [24]

Answer:

Optio a is rhe right one

i m not sure

6 0
3 years ago
Read 2 more answers
Which of the functions graphed below has a removable discontinuity?<br> A<br> B<br> C<br> D
PtichkaEL [24]
<h2>Answer with explanation:</h2>

We know that a removable discontinuity occurs when:

The left and the right hand limit of the function exist at a point and are equal but is unequal to the function's value at that point.

Also it is a  point on the graph such that it is undefined at that point.

The graph that has a removable discontinuity is attached to the answer.

Since, at x=0 the left hand and the right hand limit of the function exist but the function is not defined at x=0 , since in the graph there is a open circle at x=0 that means that the point is removed from the range.

5 0
3 years ago
Read 2 more answers
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