Answer:
0.21 g
Explanation:
The equation of the reaction is;
NaCl(aq) + AgNO3(aq) -----> NaNO3(aq) + AgCl(s)
Number of moles of NaCl= 0.0860 g /58.5 g/mol = 0.00147 moles
Number of moles of AgNO3 = 30/1000 L × 0.050 M = 0.0015 moles
Since the reaction is 1:1, NaCl is the limiting reactant.
1 mole of NaCl yields 1 mole of AgCl
0.00147 moles of NaCl yields 0.00147 moles of AgCl
Mass of precipitate formed = 0.00147 moles of AgCl × 143.32 g/mol
= 0.21 g
Answer:
what
Explanation:
I cant see your question yet
When it switches to a lower orbital, the atom emits energy in the form of photons. Your answer is C.
It is the substance that is totally consumed when the chemical reaction is complete....
Answer:
Explanation:
In this question, we have to start with the calculation of the <u>amount of drug in each powder</u>:
Powder A: Total mass of 0.5 Kg percentage of 0.038%
Powder B: Total mass of 10 Kg percentage of 0.043%
<u>The total mass of powder would be</u>:
<u>The total mass of drug would be</u>:
Now we can calculate the <u>percentage</u>:
I hope it helps!