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JulsSmile [24]
3 years ago
6

Commercially available concentrated sulfuric acid is 17.2M . Calculate the volume of concentrated sulfuric acid required to prep

are 5.00 L of 2.50M solution.
Chemistry
1 answer:
Dimas [21]3 years ago
5 0

Answer:

0.727 l.

Explanation:

For the new dilute Sulphuric acid,

Number of moles = molar concentration × volume

= 2.5 × 5

= 12.5 mol

Volume of concentrated solution = 12.5/17.2

= 0.727 l of 17.2 M of sulphuric acid to be diluted.

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Why is the chemistry of actinoids complicated?
gladu [14]

Answer:

Explanation:

Actinoids are the series have 15 element in the periodic table.

Chemistry of actinoids are complicated because of the following reasons.

  • Their outer most orbitals are 6d and 7s but most of the electrons resides in 5f orbitals. These orbitals are most exposed to environment and incoming electron picked up by 5f orbital instead of 6d or 7s orbitals.
  • They are radioactive elements that couldn't be handle in normal condition to study their properties.
  • Their f-orbital can accommodate 14 electrons and they have many variable oxidation state.
  • 5d electron donot contribute in the formation of chemical bonds.
  • They have a very strong tendency to make complexes
  • Most of the actinoides are artificial and are in very minute in amount. they are in very less quantity that is amounts found in nano-grams so are more expensive too and
  • As they are radioactive so their half life is very short and in very less time the decay occur so couldn't be study as upon decay their actual properties changed.

Due to all the above reasons it make difficult for a chemist to study about the chemical properties of actinoids.

8 0
3 years ago
The control rods are made of what materials
tiny-mole [99]
A rod of a neutron-absorbing substance used to vary the output power of a nuclear reactor.
8 0
3 years ago
Occurs when a melt is produced when the minerals with the lowest melting temperature melt, while the other minerals remain solid
FrozenT [24]
The answer is Partial melting.
4 0
3 years ago
Consider the equation: 2 nan3 (s) 2 na (s) + 3 n2. what is the mass of nan3 needed to produce 17.2 l nitrogen at stp?
Lerok [7]
The  mass  of NaN3  needed  to produce 17.2  L  nitrogen   at  STP is  calculated as  follows

find the  moles of N2   produced  at  STP
At  STP  1mole  of  gas =  22.4  L ,  what about  17.2 L  of  nitrogen

by cross  multiplication

= (1 mole x17.2  L)/ 22.4 L= 0.768  moles

2NaN3 =2Na  +3 N2
by   use of  mole ratio  between NaN3  to N2  (2:3) the  moles  of NaN3  =  0.768  x2/3 =  0.512  moles  of NaN3

mass of NaN3  is therefore =moles of NaN3  xmolar  mass of NaN3

=0.512moles  x 65 g/mol =33.28 grams  of NaN3



3 0
3 years ago
10.6 grams if NA2CO3 is dissolved in water to make 1.25 liters of solution. What is the molarity of the solution?
Debora [2.8K]

Answer::Molarity = 0.08 MExplanation:Given data:Mass of sodium carbonate = 10.6 gVolume of water = 1.25 LMolarity of solution = ?Solution:First of ... 10.6 grams of Na2CO3 is dissolved in water to make 1.25 liters of solution.

7 0
3 years ago
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