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JulsSmile [24]
3 years ago
6

Commercially available concentrated sulfuric acid is 17.2M . Calculate the volume of concentrated sulfuric acid required to prep

are 5.00 L of 2.50M solution.
Chemistry
1 answer:
Dimas [21]3 years ago
5 0

Answer:

0.727 l.

Explanation:

For the new dilute Sulphuric acid,

Number of moles = molar concentration × volume

= 2.5 × 5

= 12.5 mol

Volume of concentrated solution = 12.5/17.2

= 0.727 l of 17.2 M of sulphuric acid to be diluted.

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ladessa [460]

Answer:D - adding a catalyst

Explanation:

4 0
3 years ago
What is the pH of a 0.0042 M hydrochloric acid solution?
babymother [125]

Answer:

E) 2.38

Explanation:

The pH of any solution , helps to determine the acidic strength of the solution ,

i.e. ,

  • Lower the value of pH , higher is its acidic strength

and ,

  • Higher the value of pH , lower is its acidic strength .

pH is given as the negative log of the concentration of H⁺ ions ,

hence ,

pH = - log H⁺

From the question ,

the concentration of the solution is 0.0042 M , and being it a strong acid , dissociates completely to its respective ions ,

Therefore , the concentration of H⁺ = 0.0042 M .

Hence , using the above equation , the value of pH can be calculated as follows -

pH = - log H⁺

pH = - log ( 0.0042 M )

pH =  2.38 .

4 0
4 years ago
What piece of equipment is used to measure: length
avanturin [10]

Answer:

Ruler

Explanation:

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8 0
3 years ago
Read 2 more answers
How many grams of aluminum chloride are needed to react completely with 1.084g lithium sulfide?
Oksi-84 [34.3K]
Molar mass :

Li₂S = <span>45.947 g/mol

AlCl</span>₃ = <span>133.34 g/mol

</span><span>3 Li</span>₂<span>S + 2 AlCl</span>₃<span> = 6 LiCl + Al</span>₂S₃

3 * 45.947 g Li₂S ----------> 2 * <span>133.34 g AlCl</span>₃
1.084 g Li₂S ----------------> ?

Mass Li₂S = 1.084 * 2 * 133.34 / 3 * 45.947

Mass Li₂S = 289.08112 / 137.841

Mass Li₂S = 2.0972 g 

hope this helps!

5 0
3 years ago
A students drawing of a nitrogen atom is shown. What change would make the model more accurate?
zubka84 [21]

Answer:

C - show 7 neutrons in the nucleus

Explanation:

Use process of elimination:

-Answer A will not work because electrons are not in the nucleus.

-Answer B will change the atom's identity from nitrogen to fluorine; it will not work.

-Answer D will create a nitrogen ion, which is not what the prompt is asking for (an atom); it will not work.

The only logical answer is C, as that is the only one that is also true.

8 0
3 years ago
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