Answer:
The pH of the solution is 1.00
Explanation:
The pH gives us an idea of the acidity or basicity of a solution. More precisely, it indicates the concentration of H30 + ions present in said solution. The pH scale ranges from 0 to 14: from 0 to 7 corresponds to acid solutions, 7 neutral solutions and between 7 and 14 basic solutions. It is calculated as:
pH = -log (H30 +)
The concentration of the H30+ ions is 0,1M:
pH= -log (0,1)
<em>pH=1.00</em>
Answer:
4.56×10^-10
Explanation:
Co(OH)2(s)<------->Co^2+(aq) + 2OH^-(aq)
Co^2+(aq) + 6NH3(aq) ---------->[Co(NH3)6]^2+(aq)
Overall equation:
Co(OH)2(s)+ 6NH3(aq) ---------->[Co(NH3)6]^2+(aq) + 2OH^-(aq)
The increased solubility of the cobalt salt in the presence of ammonia is as a result of the formation of the hexammine cobalt II complex shown above.
Knet= Ksp×Kf
Ksp of Co(OH)2= 5.92 × 10^-15.
Kf= 7.7 x 10^4
Knet= 5.92 × 10^-15 × 7.7 x 10^4
Knet= 4.56×10^-10
Note Knet is the equilibrium constant of the overall reaction.
Hydrosphere because it is water and water is where the dolphins swim.
Answer:
0.04 mol
Explanation:
Given data:
Mass of barium = 5.96 g
Moles of barium = ?
Solution:
Formula:
Number of moles = mass/molar mass
Molar mass of barium = 5.96 g/ 137.33 g/mol
Number of moles = 0.04 mol
Thus the number of moles of barium in 5.96 g are 0.04 moles. The chemist weight out the 0.04 moles .
The Ions present in CaCl₂ are,
Ca²⁺ Cl⁻ Cl⁻
Means 1 formula unit contains 1 Ca²⁺ ion and 2 Cl⁻ ions.
Also, 1 mole of CaCl₂ contains 6.022 × 10²³ formula units.
So, 1 mole formula units of CaCl₂ contain,
2 × 6.022 × 10²³ = 1.20 × 10²⁴ Cl⁻ Ions
Now, Calculating number of moles contained by 220 g of CaCl₂,
As,
110.98 g of CaCl₂ = 1 mole
Then,
220 g of CaCl₂ = X moles
Solving for X,
X = (220 g × 1 mol) ÷ 110.98 g
X = 1.98 moles
As,
1 mole contained = 1.20 × 10²⁴ Cl⁻ Ions
Then,
1.98 mole will contain = X Cl⁻ Ions
Solving for X,
X = (1.98 mol × 1.20 × 10²⁴ Ions) ÷ 1mol
X = 2.38 × 10²⁴ Cl⁻ Ions
