The hypothesis is given as
H0: μd< 0
H1: μd > 0
<h3>How to solve for the hypothesis.</h3>
The null hypothesis is given as
H0: μd< 0
<h3>The alternative hypothesis is given as </h3>
H1: μd > 0
SWe have to find the value of s
we would use this formula s = sqrt [ (Σ(di - d)^2 / (n - 1) ]
This gives us 3.454
Next we have to determine the standard error
s / √(n)
3.454/2.8284
= 1.22
Degree of freedom = 8 - 1
= 7
t = (x1 - x2) - D / S.E
= 1.025
Find t critical at 0.10
= 1.895
P-value = 0.1697
d. Given that p value is greater thatn 0.1 we fail to reject the null hypothesis.
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I'm pretty sure its B but I would double check before you put the answer in :)
5 minutes
32/160 = 0.2 mile/min
0.2x = 1
0.2x/0.2 = 1/0.5
x = 5
5 minutes
Answer: it is the 4 one
Step-by-step explanation:
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now
2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4
At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real.
Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result.
For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196
No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.
So x^2 = -4 has no real solutions. Taking the square root of both sides leads to
x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values
