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Masteriza [31]
3 years ago
8

What is the area of a regular octagon with an apothem 16 inches long and a side 19 inches long?

Mathematics
1 answer:
Nitella [24]3 years ago
8 0
Area = (# of sides) * (side length) * (apothem) / 2
area = (8 * 19 * 16) / 2
area = <span> <span> </span></span>1,216 square inches


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PLEASE HELP!!!!!!!
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4 0
3 years ago
What % of 40 is 15? Please put how u do it
andriy [413]

Answer:

37.5

Step-by-step explanation:

so x% of 40 is 15

the equation for that is

x/100 * 40 = 15

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6 0
3 years ago
Read 2 more answers
Unknown variables in Equations <br><br> 1. 7=w/14<br> 2.42/n=7<br> 3. 324/18=a
belka [17]

Answer:

w = 98

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Step-by-step explanation:

Question 1)

7 = w/ 14

All you need to do is multiply each side by 14 to find w:

7(14) = W

W = 98

Question 2)

42/n = 7

For this one, first multiply each side by "n":

42 = 7n

and then divide both sides by 7:

N = 6

Question 3)

All you need to do for this question is divide 324 by 18 to find "a":

324/18 = a

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I hope this helps!

-TheBusinessMan

4 0
3 years ago
Can someone please help me
Aneli [31]

Answer:

r = 5

Step-by-step explanation:

To solve for r, plug in the change in x values and change in y values, since the hypotenuse is simply the diagonal of both the y-coordinate and x-coordinates shown via drawing legs on the vertical and horizontal axis. So, since (0,0) is the initial point, r = sqr[(-4-0)^2 + (-3-0)^2 = sqr(16 + 9) = 5.

Now, the angle theta is the angle in which the sine, cosine, and tangent ratios are found. Simply use opposite over hypotenuse for sine, adjacent over hypotenuse for cosine, and opposite over adjacent for tangent using theta as the angle in which these values are obtained.

5 0
2 years ago
john worked five less than twice as many hours as Jane did how many hours did each work if together they worked 97 hours
il63 [147K]

John worked 61 yours and Jane worked 36 hours


6 0
3 years ago
Read 2 more answers
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