Since the problem states "at least" we need to also find probability of 3 H or 4 H or 5 H
Now find the probability of flipping a head 4 times;

⁴
= (1/16)
Now probability of flipping a head 3 times: (4C3)(1/2)⁴ = 4/16
Probability of flipping a head 2 times; (4C2)(1/2)⁴=6/16
(1/16)+(4/16)+(6/16)=11/16
Probability of flipping a fair coin 4 times with at least 2 heads is 11/16.
Hope I helped :)
Answer:
≈ 10.63
Step-by-step explanation:
Pythagorean Theorem... Possibly the most easy theory in math once you understood it.
Here's the formula.
AB would be the hypothenuse
BC would be the opposite
CA would be the Adjacent.
But let's not make it complicated though, the question is actually quite easy.
You are asked to find AB, the hypothenuse.
The hypothenuse would be C.
BC and CA would be A and B.
It doesn't matter where are you going to place the numbers.
So,
= 113
Now we would have to square root 113 since
is an irrational number, and the question asks you to round ro the nearest tenth.
=10.63014581
≈ 10.63
Your answer would be 10.63
Hope this answer helped :)
Amber can make a possible number of 12 different teams
4.85 is the answer because if you subtract 51.2 from 56.05 you get your answer